Answer:
7. Option D. 8.4×10¯⁴ m/s North.
8. Option B. 2 m/s
Explanation:
7. Determination of the speed of the snail.
The following data were obtained from the question:
Distance travalled (d) = 15 m
Time (t) = 300 mins
Speed (S) =?
Next, we shall convert 300 mins to secs. This can be obtained as follow:
1 min = 60 secs
Therefore,
300 mins = 300 × 60 = 18000 secs
Finally, we shall determine the speed of the snail as follow:
Distance travalled (d) = 15 m
Time (t) = 18000 secs
Speed (S) =?
Speed = Distance travelled /time
Speed = 15 / 18000
Speed = 8.3×10¯⁴ m/s
Since the snail travelled due north, the speed is therefore 8.3×10¯⁴ m/s North.
8. Determination of speed of the runner.
The following data were obtained from the question:
Distance travalled = 8 m
Time = 4 secs
Speed =?
Speed = Distance travalled / time
Speed = 8/4
Speed = 2 m/s
Therefore, the speed of the runner is 2 m/s.
