The formula for finding the volume of a cube is

, where s is the side length.
The formula for a cube with each side length doubled is

, or 8<span>s.
</span><span>If all the dimensions of a cube are doubled, then the new volume is
eight times greater.</span>
A percentage figure shows that the quantity of parts per one hundred a segment sum compares to. For instance, "85 percent" is another method for saying "85 sections for each 100." To calculate a percentage, the entire sum must be known, in addition to the percentage or portion amount.
Hello,
x,y,z∈ IN





==>
x∈{35,36,37}
y∈{47,48,49}
z∈{141,144,147}
We must go futher:
if x=35 then y=4*35/3=46.666 not good , not whole
if x=36 then y=4*36/3=48 ok
if x=37 then y=37*4/3=49.333.. not good
So there is only one solution (36,48,144) for (x,y,z)
No problem with z for z=3/1*4/3*x=4x ==>whole.
Answer:
After 5 months the cost of the two phones and monthly service be the same.
Step-by-step explanation:
1st service cost = $50 + $40x, where "x" represents the number of months
2nd service cost = $50x
Now we have to find the number of months the cost of the two phones and monthly service be the same.
Now we have to equivate and find the value of x.
50x = 50 + 40x
Subtracting 40x from both sides, we get
50x - 40x = 50 + 40x - 40x
10x = 50
Dividing both sides by 10, we get
x = 50/10
x = 5
After 5 months the cost of the two phones and monthly service be the same.
Hope you will understand the concept.
Thank you.
Answer:
5400 cubes can be fit into the prism.
Step-by-step explanation:
We are given the dimensions of prism as:
5 units by 5 units by 8 units i.e. 5 units×5 units×8 units.
Hence, the volume of the prism is given by:
Volume of prism=5×5×8=200 cubic units
Also the edge length of cube is given by= 1/3 unit.
Hence volume of 1 cube=
Hence volume of 1 cube= (1/27) cubic units.
Let 'n' cubes can be fitted into the prism.
Hence we have the relation as:
Volume of prism=n×Volume of 1 cube.
200=n×(1/27)
n=200×27
n=5400
Hence 5400 cubes can be fitted into the prism.
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NUMBER THREE</em></u></h2>