1. If the total baggage fees were equal, you would have to equate the two situations. Suppose x is the weight above the limit on the flight home, while y is the weight above the limit on the flight back to college. Then, the equation would be:
20 + 8x = 26 + 5y
Now, we have two unknowns, but only one independent equation. This is unsolvable unless we make an assumption. Suppose the excess weight for both trips are the same such that x=y, then,
<em>20 + 8x = 26 + 5x</em>
2. Then, we solve for x.
8x - 5x = 26 - 20
3x = 6
x = 6/3 = <em>2 lb</em>
Thus, Elizabeth's bag was 2 lb over the weight limit.
3. The total baggage fee would then be:
20+8(2) = 26 + 5(2) = <em>$36</em>
Answer:
Jackson s reasoning is incorrect this because if we multiply with numbers smaller than zero what we get is a smaller number: 54•0.2=27 etc...
Answer:
False, there are no solutions
Step-by-step explanation:
y = 2x+4
y = 2x+10
The slopes are the same (2) but the y intercepts are different
These lines are parallel with different intercepts
They will never intersect so there are no solutions
Answer:
My name is lil uzi vert
Step-by-step explanation:
maybach maybach
60 • .25 = 15
60 - 15 = 45
45 + 5 = $50
Brian paid $50 in total