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Dominik [7]
3 years ago
14

Approximately how many times as great is the volume of a grapefruit with a diameter 16 cm as the volume of a lime with a diamete

r 8 cm
Mathematics
1 answer:
SIZIF [17.4K]3 years ago
8 0

Answer: The volume of the grapefruit is approximately 8 times as great as the volume of the lime.

Step-by-step explanation:

You need to use the formula for calculate the volume of a sphere. This is:

V=\frac{4}{3}\pi  r^3

Where "r" is the radius.

<u>Volume of the grapefruit</u>

You know that its diameter is 16 centimeters.

Since the radius is half the diameter, you get that its volume is:

V_g=\frac{4}{3}\pi  (\frac{16\ cm}{2}) ^3\\\\V_g= 2,144.66\ cm^3

<u> Volume of the lime</u>

According to the information given in the exercise, the diameter of the lime is 8 centimeters.

As it was explained above, the radius is half the diameter. Knowing that, you get that volume of the lime is the shown below:

V_l=\frac{4}{3}\pi  (\frac{8\ cm}{2}) ^3\\\\V_l= 268.08\ cm^3

In order to find approximately how many times as great is the volume of theat grapefruit as the volume of that lime, you need to divide the volumes calculated above. Then:

\frac{2,144.66\ cm^3}{268.08\ cm^3}\approx8\ times

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Answer:

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Step-by-step explanation:

<u>Funciones Trigonométricas</u>

La identidad principal en trigonometría es:

sen^2A+cos^2A=1

Si sabemos que A es un ángulo agudo (que mide menos de 90°), su seno y coseno son positivos.

Dado que Sen A = 4/5, calculamos el coseno:

cos^2A=1-sen^2A

Sustituyendo:

\displaystyle cos^2A=1-\left(\frac{4}{5}\right)^2

\displaystyle cos^2A=1-\frac{16}{25}

\displaystyle cos^2A=\frac{25-16}{25}

\displaystyle cos^2A=\frac{9}{25}

Tomando raíz cuadrada:

\displaystyle cos\ A=\sqrt{\frac{9}{25}}=\frac{3}{5}

La tangente se define como:

\displaystyle \tan A=\frac{sen\ A}{cos\ A}

Substituyendo:

\displaystyle \tan A=\frac{\frac{4}{5}}{\frac{3}{5}}

\displaystyle \tan A=\frac{4}{3}

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2 years ago
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I hope this helps you



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