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Dominik [7]
3 years ago
14

Approximately how many times as great is the volume of a grapefruit with a diameter 16 cm as the volume of a lime with a diamete

r 8 cm
Mathematics
1 answer:
SIZIF [17.4K]3 years ago
8 0

Answer: The volume of the grapefruit is approximately 8 times as great as the volume of the lime.

Step-by-step explanation:

You need to use the formula for calculate the volume of a sphere. This is:

V=\frac{4}{3}\pi  r^3

Where "r" is the radius.

<u>Volume of the grapefruit</u>

You know that its diameter is 16 centimeters.

Since the radius is half the diameter, you get that its volume is:

V_g=\frac{4}{3}\pi  (\frac{16\ cm}{2}) ^3\\\\V_g= 2,144.66\ cm^3

<u> Volume of the lime</u>

According to the information given in the exercise, the diameter of the lime is 8 centimeters.

As it was explained above, the radius is half the diameter. Knowing that, you get that volume of the lime is the shown below:

V_l=\frac{4}{3}\pi  (\frac{8\ cm}{2}) ^3\\\\V_l= 268.08\ cm^3

In order to find approximately how many times as great is the volume of theat grapefruit as the volume of that lime, you need to divide the volumes calculated above. Then:

\frac{2,144.66\ cm^3}{268.08\ cm^3}\approx8\ times

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Find all pairs of natural numbers which can be the solution to the equation a+b=42.
Setler [38]

Answer:

(1,41), (2,40), (3,39), (4,38), (5,37), (6,36), (7,35), (8,34), (9,33), (10,32), (11,31), (12,30), (13,29), (14,28), (15,27), (16,26), (17,25), (18,24), (19,23), (20,22), (21,21), (22,20), (23,19), (24,18), (25,17), (26,16), (27,15), (28,14), (29,13), (30,12), (31,11), (32,10), (33,9), (34,8), (35,7), (36,6), (37,5), (38,4), (39,3), (40,2), (41,1).

Step-by-step explanation:

To find all pairs of natural numbers which are solution to a+b=42, we need to first choose a value to one of them (let's choose 'a'), and that value will be the lowest possible, so we begin with a=1, and then we increase to 2, and 3, and so on.

For each value of a, we calculate the value of b using the equation.

So, starting with a=1, we have that b=41

Then, with a=2, we have that b=40, and so on.

Doing this until a=41 (so b=1 will be the lowest value possible for b), we have the pairs of natural number we want:

(1,41), (2,40), (3,39), (4,38), (5,37), (6,36), (7,35), (8,34), (9,33), (10,32), (11,31), (12,30), (13,29), (14,28), (15,27), (16,26), (17,25), (18,24), (19,23), (20,22), (21,21), (22,20), (23,19), (24,18), (25,17), (26,16), (27,15), (28,14), (29,13), (30,12), (31,11), (32,10), (33,9), (34,8), (35,7), (36,6), (37,5), (38,4), (39,3), (40,2), (41,1).

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jolli1 [7]
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Read 2 more answers
The area ( l x w ) of the postcard is 24 square inches. What is the width b of the message (in inches)?
pentagon [3]

area = (l)(w)(h)

24 = 4(3 + b)

24 = 12 + 4b

-12 on both sides

12 = 4b

/4 on both sides

b = 3 inches

Substitute b = 3 inches in width

3 + b

3 + 3 = 6 inches

Answer:

width = 6 inches

5 0
3 years ago
&lt;
irinina [24]

Answer:

Step-by-step explanation:

Remark

f(x) = 9x^2 - 5x + 3 is given. The notation means that wherever you see and x on the right, you replace it with the x in the brackes on the left. f(3) is a direction, not anything you have to adjust or manipulate.

Solution

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f(-3) = 9 * 9 + 15 + 3

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Answer: f(-3) = 99

8 0
2 years ago
What is the measure of
Sever21 [200]

Answer:

The measure of ∠G is 59°

Step-by-step explanation:

<em>When </em><em>two secants</em><em>, intersect at </em><em>a point outside a circle</em><em> then the </em><em>measure of the angle formed between them</em><em> is </em><em>one-half the positive difference of the measures of the intercepted arcs.</em>

<em></em>

In the given figure

∵ GT is a secant that intersects the circle at points H and T

∵ GE is a secant that intersects the circle at points F and E

∴ The intercepted arcs are HF and TE

∵ GT ∩ GE at G

∵ Point G is outside the circle

→ By using the rule above

∴ m∠G = \frac{1}{2} (m arc TE - m arc HF)

∵ m arc TE = 175°

∵ m arc HF = 57°

→ Substitute them in the rule above

∵ m∠G = \frac{1}{2} (175 - 57) = \frac{1}{2} (118)

∴ m∠G = 59

∴ The measure of ∠G is 59°

8 0
3 years ago
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