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Amiraneli [1.4K]
3 years ago
8

A is at (-2, 1) and B is at (4, -1).

Mathematics
1 answer:
Dmitry_Shevchenko [17]3 years ago
7 0

Answer:

<em>The coordinates of P are (1,0)</em>

Step-by-step explanation:

<u>Midpoint</u>

The midpoint (xm,ym) of a segment defined by points (x1,y1) and (x2,y2) is calculated as follows:

\displaystyle x_m=\frac{x_1+x_2}{2}

\displaystyle y_m=\frac{y_1+y_2}{2}

We need to find the coordinates of P which is equidistant from the endpoints A=(-2,1) and B=(4,-1).

Calculate the midpoint:

\displaystyle x_m=\frac{-2+4}{2}=1

\displaystyle y_m=\frac{1-1}{2}=0

Thus, the coordinates of P are (1,0)

Note the midpoint does not lie on the y-axis but on the x-axis.

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How many yards long is John's new surfboard if it is 7 feet long
kow [346]

Answer:

A)

Step-by-step explanation:

6 0
3 years ago
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What’s the degree 2xy5
frutty [35]

Answer:

  6

Step-by-step explanation:

The degree of the term

  2xy^5

is the sum of the exponents of the variables, so is 1+5 = 6.

The degree of the term is 6.

6 0
3 years ago
Multiply or divide the following measurements. Be sure each answer you enter contains the correct number of significant digits.
nydimaria [60]

Answer:

93.4 g/mL x 20. mL = 1868g.

489.7m / 53.061 s = 9.23 m/s

216.3 m/66.4 s = 3.26 m/s.

Step-by-step explanation:

Let's analyze each case.

93.4 g/mL x 20. mL

Hewe we are multiplying g/ml*ml. So we have the answer is (g*ml/ml) = g.

So

93.4 g/mL x 20. mL = 1868g.

489.7m / 53.061 s

We are dividing a measurement in m by a measurement in s. So the answer is in m/s.

So

489.7m / 53.061 s = 9.23 m/s

216.3 m/66.4 s

Same as above.

We are dividing a measurement in m by a measurement in s. So the answer is in m/s.

So

216.3 m/66.4 s = 3.26 m/s.

6 0
3 years ago
The combustion of one gallon of automobile fuel produces about 5 pounds of carbon (in CO₂). Two autos are making a trip of 600 m
rewona [7]

Answer:

Approximately 50 pounds less carbon (in CO₂) will be produced by the second auto on this trip.

Step-by-step explanation:

We have been given that the combustion of one gallon of automobile fuel produces about 5 pounds of carbon (in CO₂). Two autos are making a trip of 600 miles.

Let us find amount of fuel used by autos by dividing the total distance by their mileage.

\text{Fuel used by 1st auto}=\frac{\text{ 600 miles}}{\frac{\text{ 20 miles}}{\text{gallon}}}

\text{Fuel used by 1st auto}=\frac{\text{ 600 miles}}{\text{ 20 miles}}\times \text{gallon}

\text{Fuel used by 1st auto}=30 \text{ gallons}

\text{Fuel used by 2nd auto}=\frac{\text{ 600 miles}}{\frac{\text{ 30 miles}}{\text{gallon}}}

\text{Fuel used by 2nd auto}=\frac{\text{ 600 miles}}{\text{ 30 miles}}\times \text{gallon}

\text{Fuel used by 2nd auto}=20 \text{ gallons}

Let us find the difference of fuel used by both autos.

\text{Number of gallons that 2nd auto used less than 1st auto}=30-20

\text{Number of gallons that 2nd auto used less than 1st auto}=10

Since one gallon of automobile fuel produces about 5 pounds of carbon, so 10 gallons of fuel will produces 5\times 10=50 pounds of carbon.

Since 2nd auto used 10 gallons less than 1st auto, therefore, 2nd auto will produce 50 pounds less carbon than 1st auto.

8 0
3 years ago
Solve the following inequality. |3n-2|-2&lt;1
disa [49]

Answer: \frac{-1}{3} < n < \frac{5}{3}

<u>Step-by-step explanation:</u>

| 3n - 2 | - 2 < 1

<u>               +2 </u> <u>+2 </u>

| 3n - 2 |       < 3

3n - 2 < 3     and     3n - 2 > -3

<u>      +2 </u> <u>+2   </u>              <u>     +2 </u>  <u> +2 </u>

3n       < 5      and     3n      > -1

       n <  \frac{5}{3}       and         n > \frac{-1}{3}

\frac{-1}{3} < n < \frac{5}{3}

Interval Notation:  (\frac{-1}{3},\frac{5}{3})

Graph:  \frac{-1}{3} o--------------------o \frac{5}{3}


7 0
3 years ago
Read 2 more answers
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