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3 years ago

I'll add a photo of the problem!

Mathematics

1 answer:

Lyrx [107]3 years ago

6 0

Answer:

its d

Step-by-step explanation:

the number 30 is not listed in the problem there that is info that is not there

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Simplify the expression enter the answer in the box 5 1/6 - 7 1/3

OlgaM077 [116]

Hi hope this helps! Answer in the picture

5 0

3 years ago

Solving a right triangle (ROUND TO THE NEAREST TENTH)

Kay [80]

Answer:

see explanation

Step-by-step explanation:

The sum of the 3 angles in a triangle = 180°

Subtract the sum of the given angles from 180 for B

B = 180° - (90 + 40)° = 180° - 130° = 150°

--------------------------------------------------------------

sin40° = $\frac{opposite}{hypotenuse}$ = $\frac{a}{21}$

Multiply both sides by 21

21 × sin40° = a, thus

a ≈ 13.5 ( to the nearest tenth )

--------------------------------------------------------------

cos40° = $\frac{adjacent}{hypotenuse}$ = $\frac{b}{21}$

Multiply both sides by 21

21 × cos40° = b, thus

b ≈ 16.1 ( to the nearest tenth )

3 0

4 years ago

Jane is is charge of making a banner for the basketball game this Saturday. She measures how long the banner is before painting

RSB [31]

Answer:

The measurement which Jane finds to be 10 meters is the length of the banner.

Step-by-step explanation:

The measurement of 10 meters which Jane found after measuring how long the banner is before painting is the LENGTH of the banner.

This is clear from the unit of what she finds (meters). It only indicates the measurement of one part of the banner, even though a banner has two parts, the length and width.

It is possible to find the AREA, or PERIMETER, or LENGTH.

But what she finds is the LENGTH of the banner. If it was Area or Perimeter, the unit would have been square meters.

7 0

3 years ago

Solve the system, using any method. y = x + 2 and x + 2y = 25

Leni [432]

$Elimination\ method\\\\\left\{\begin{array}{ccc}y=x+2&|subtract\ "x"\ from\ both\ sides\\x+2y=25\end{array}\right\\+\left\{\begin{array}{ccc}-x+y=2\\x+2y=25\end{array}\right|add\ the\ equations\ sides\ \\\----------\\.\ \ \ \ \ \ \ 3y=27\ \ \ \ \ |divide\ both\ sides\ by\ 3\\.\ \ \ \ \ \ \ \ \ \ y=9\\\\subtitute\ y=9\ to\ second\ equation\\x+2(9)=25\\x+18=25\ \ \ \ \ \ \ |subtract\ 18\ from\ both\ sides\\x=7\\\\Solution:x=7\ and\ y=9\to(7;\ 9)$