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slavikrds [6]
3 years ago
7

What is the domain of the function? x + 3 f(x) = VX + 3

Mathematics
1 answer:
ahrayia [7]3 years ago
3 0

Your question is a little ambiguous, but I am assuming that you meant to say the function f(x) = x+3

Thus, I am solving your question based on assuming the function such as

f(x)=x+3

But, it would still clear your concept, no matter what the function is.

Answer:

we conclude that

\mathrm{Domain\:of\:}\:x+3\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-\infty \:

The graph is also attached.

Step-by-step explanation:

Given the function

f(x)=x+3

We know that the domain of a function is the set of input or argument values for which the function is real and defined.

As the function has no undefined points nor domain constraints.

Thus, the domain is

-\infty \:

Therefore, we conclude that

\mathrm{Domain\:of\:}\:x+3\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-\infty \:

The graph is also attached.

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Nata [24]

the height of the house is 408ft .

<u>Step-by-step explanation:</u>

Here we have , To estimate the height of a house Katie stood a certain distance from the house and determined that the angle of elevation to the top of the house was 32 degrees. Katie then moved 200 feet closer to the house along a level street and determined the angle of elevation was 42 degrees. We need to find  What is the height of the house . Let's find out:

Let  y is the unknown height of the house, and x is the unknown number of feet she is standing from the house.

Distance of house from point A( initial point ) = x ft

Distance of house from point B( when she traveled 200 ft towards street  = x-200 ft

Now , According to question these scenarios are of right angle triangle as

At point A

⇒ Tan32 =\frac{Perpendicular}{Base}= \frac{y}{x}

⇒ Tan32 = \frac{y}{x}

⇒ y=x(Tan32 )       ..................(1)

Also , At point B

⇒ Tan42 = \frac{y}{x-200}

⇒ y=(x-200)(Tan42)     ..............(2)

Equating both equations:

⇒ (x-200)(Tan42) = x(Tan32)

⇒ x(Tan42-Tan32)=Tan42(200)

⇒ x=\frac{Tan42(200)}{(Tan42-Tan32)}

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Putting  x=653ft in  y=x(Tan32 )  we get:

⇒  y=x(Tan32 )    

⇒  y=653(Tan32 )

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4 0
3 years ago
If Diana walks forward and her angle looking to the top of the building changes to 40°, how much closer is she to the building?
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The closer Diana gets to the building, the smaller the angle becomes

Diana is 17.6 feet closer to the building

<h3>How to calculate the distance from the building</h3>

To calculate the distance between her and the building, we make use of the following tangent ratio

\tan(\theta) = \frac{h}{d}

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So, we have:

\tan(40) = \frac{130}{d}

Make d the subject

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Evaluate tan(40)

d = \frac{130}{0.8391}

d = 154.93

Initially, Diana is at a distance of 172.53.

The difference in both distance is:

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\Delta d = 17.6

Hence, Diana is 17.6 feet closer to the building

Read more about trigonometry ratios at:

brainly.com/question/4326804

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An assistant at an animal shelter wants to know the typical age of dogs admitted to the shelter. the shelter has admitted 353 do
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Step-by-step explanation:

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