A plumber charges $25 for a service call plus $50 per hour of service.

Mathematics

2 answers:

torisob [31]2 years ago

8 0

Answer:425
explanation:

bija089 [108]2 years ago

7 0

C= 50h+25

50(8)+25
C=$425

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Solve the inequality for x 3^(6x+18)<27^(3x)

Lera25 [3.4K]

Answer:

$\displaystyle x > 6$

General Formulas and Concepts:

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Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
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Addition
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Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

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Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle 3^{6x + 18} < 27^{3x}$

Step 2: Solve for x

Rewrite: $\displaystyle 3^{6x + 18} < 3^{3(3x)}$
Set: $\displaystyle 6x + 18 < 3(3x)$
Factor: $\displaystyle 3(2x + 6) < 3(3x)$
[Division Property of Equality] Divide 3 on both sides: $\displaystyle 2x + 6 < 3x$
[Subtraction Property of Equality] Subtract 3x on both sides: $\displaystyle -x + 6 < 0$
[Subtraction Property of Equality] Subtract 6 on both sides: $\displaystyle -x < -6$
[Division Property of Equality] Divide -1 on both sides: $\displaystyle x > 6$

8 0

3 years ago

Read 2 more answers

Plz help me I dont get it

wlad13 [49]

So you have to decrease £30 by 20%

To do this, an easy way would be to first take away 100% from 20% because you are DECREASING :
100 - 20 = 80

Then divide your answer by 100 :
80 / 100 = 0.8

This means 0.8 is going to be your multiplier so you do
0.8 * 30 = 24

Answer = £24

5 0

3 years ago

Solve for X. (Picture)

Ahat [919]

$-2(7-4x)=\dfrac{1}{2}(4+16x)\qquad\text{use distributive property}\\\\(-2)(7)+(-2)(-4x)=\left(\dfrac{1}{2}\right)(4)+\left(\dfrac{1}{2}\right)(16x)\\\\-14+8x=2+8x\qquad\text{subtract 8x from both sides}\\\\-14=2\qquad FALSE!!!\\\\Answer:\ \boxed{no\ solution}$