Answer:
24.3
Step-by-step explanation:
18/20 = x/20 (similar triangles)
Answer:
c = 29
Step-by-step explanation:
Law of sines is given as: 
B = 180 - (57 + 44) = 79°
b = 41
C = 44°
c = ?
Thus:

Substitute

Multiply both sides by sin 44


c = 29.0140633 ≈ 29
Answer:

Step-by-step explanation:
Given

Required
Approximate (to the nearest 100th)
This means that, we approximate at the second digit after the decimal.
So:
i.e,
Number = 39.79 [Begin approximation] 949748
The first digit after [Begin approximation] is then approximated using the following rule:


Since 9 falls in
category, the number becomes:
![Number = 39.[79+1]](https://tex.z-dn.net/?f=Number%20%3D%2039.%5B79%2B1%5D)

X/2-y/3=3/2
(6×x/2)-(6×y/3)=6×3/2
3x-2y=9______(1)
x/3+y/2=16/3
(6×x/3)+(6×y/2)=6×16/3
2x+3y=32_____(2)
(1)×3____9x-6y=27____(3)
(2)×2____4x+6y=64____(4)
(3)+(4)___13x=91
x=7
3(7)-2y=9
-2y=-12
y=6
Given:
In a two-digit number, the tens digit is 5 less than the units digit.
The number itself is five more than three times the sum of its digits.
To find:
The number.
Solution:
Let the two digit number is ab. So,

Tens digit is 5 less than the units digit.
...(i)
The number itself is five more than three times the sum of its digits.



...(ii)
Using (i) and (ii), we get





Putting b=8 in (i), we get


Therefore, the required number is 38.