What is the answer to 157.93+23.5=?

Jennifer has a savings account that earns interest at a rate of 3% per year. Jennifer deposits 1000 into the account. Which of t

Tomtit [17]

The exponential equations represents how long it will take for the account to grow to 1500 is y = 1000(b)^13.72

<h3>Exponential equations</h3>

Exponential equations are inverse of logarithmic equation. The standard exponential equation is expressed as;

y = ab^x

where

a is the base

x is the exponent

b is the rate

If Jennifer has a savings account that earns interest at a rate of 3% per year. Jennifer deposits 1000 into the account, the resulting exponential equation will be:

y = 1000(1.03)^x

If y = 1500, find the value of x

1500 = 1000(1.03)^x
1.5 = 1.03^x

ln1.5 = xln1.03
x = ln1.5/ln1.03

x = 13.72

Substitute to determine the equation

y = 1000(b)^13.72

Hence the exponential equations represents how long it will take for the account to grow to 1500 is y = 1000(b)^13.72

Learn more on exponential equation here: brainly.com/question/2456547

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4 0

2 years ago

663 round to the nearest ten

Charra [1.4K]

It is 660 because you just have to round the 3

8 0

4 years ago

Phillip is building a go-cart. The wheels he is using are 6 inches from the center to the edge of the wheel. How many inches sho

sweet [91]

Answer:37.69911184

Step-by-step explanation: r=6 r*2= d. D*pie=c

R=radis

D=Diameter

8 0

2 years ago

Which shows the list of numbers in order from least to greatest?

3241004551 [841]

Answer:

The first one

Step-by-step explanation:

Note the brackets means absolute value so the order of the first one goes like this

-1, 3/2, 2, 3, 3.5

Thus it's from least to greatest

7 0

3 years ago

Assume that the one-way commute time of an UoU student from his house to school is a normally distributed random variable which

Marizza181 [45]

Answer:

$n=(\frac{1.960(10)}{5})^2 =15.36 \approx 16$

So the answer for this case would be n=16 rounded up to the nearest integer

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

$\sigma=10$ represent the sample standard deviation

n represent the sample size

ME=5 represent the margin of error

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (2)

And on this case we have that ME =5 and we are interested in order to find the value of n, if we solve n from equation (2) we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (3)

The critical value for 95% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.025;0;1)", and we got $z_{\alpha/2}=1.96$ , replacing into formula (3) we got:

$n=(\frac{1.960(10)}{5})^2 =15.36 \approx 16$

So the answer for this case would be n=16 rounded up to the nearest integer

3 0

3 years ago