A.The sum of two products; there are two terms
Answer:
Step-by-step explanation:
(a).
Within 1 year, there would be 4 payments to be made.
therefore, PMT= 
(i) 1st payment will be :PMT $128.125
(ii) 2nd payment will be :128.125*(1.025)^1= $131.33
(iii) 3rd payment will be :128.125*(1.025)^2=$134.61
(iv) 4th payment will be :128.125*(1.025)^3=$137.98
Hence the payments are: $128.125, $131.33, $134.61, and $137.98.
(b).
The size of the final payment
where m 4 *5= 20

Multiply the first equation by 7 and the second equation by 2, and then add.
Step-by-step explanation:
2f - 5g=-9
-7f + 3g=4
To eliminate any variable , we need to make the coefficients same with different sign and add it
the coefficient of 'f' in first equation is 2
the coefficient of 'f' in second equation is -7
We already have different sign so we make the coefficients same
To make the coefficient same , we multiply the first equation by 7 and second equation by 2
So equation becomes
14f - 35g = -63
-14f + 6g = 8
Now when we add both equations, 'f' gets cancelled
-29g = -55
One trillion four hundred billion
Answer:
The simplified version of
is
.
Step-by-step explanation:
The given expression is
![\sqrt[3]{135}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B135%7D)
According to the property of radical expression.
![\sqrt[n]{x}=(x)^{\frac{1}{n}}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%7D%3D%28x%29%5E%7B%5Cfrac%7B1%7D%7Bn%7D%7D)
Using this property we get
![\sqrt[3]{135}=(135)^{\frac{1}{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B135%7D%3D%28135%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D)
![\sqrt[3]{135}=(27\times 5)^{\frac{1}{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B135%7D%3D%2827%5Ctimes%205%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D)
![\sqrt[3]{135}=(3^3\times 5)^{\frac{1}{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B135%7D%3D%283%5E3%5Ctimes%205%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D)
![[\because (ab)^x=a^xb^x]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%28ab%29%5Ex%3Da%5Exb%5Ex%5D)
![[\because \sqrt[n]{x}=(x)^{\frac{1}{n}}]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Csqrt%5Bn%5D%7Bx%7D%3D%28x%29%5E%7B%5Cfrac%7B1%7D%7Bn%7D%7D%5D)
![\sqrt[3]{135}=3\sqrt[3]{5}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B135%7D%3D3%5Csqrt%5B3%5D%7B5%7D)
Therefore the simplified version of
is
.