I believe the answer would be (1) because they are not directly related
Secxcotx=cscx
1/cos * cos/sin =cscx
cos/sincos=csc
1/sin=csc
The square roo it 7.07106781 i
2x +4y =10x-3y =12
2x +4y =12 -----eq. 1
10x-3y =12 -------eq.2
2x =12 -4y [using eq. 1]
x = (12-4y)/ 2
= 6 -2y
Now, substitute the value of x in eq. 2
10 (6-2y)-3y =10
60 -20y -3y =10
-23 y = 10 -60
y = -50 / -23
y = 50/23
Now, substitute this value of y in any equations given above
10 x-3 (50/23) =12
10x - (150/23)= 12
x= 426/230
