H(x) = x ^ 2 - 2 g(x) = 4x + 1 Find (h•g)(x)

Madisyn is planting crops in a triangular garden. She is trying to find the amount of fencing

MrRissso [65]

Answer:

Fencing needed = 20.8 units

Step-by-step explanation:

From the figure attached,

Given: Triangle ABC with vertices A(0, 6), B(6, 5) and C(5, -1).

We have to find the length of fence required to cover the triangular garden.

Amount of fencing required = Perimeter of the triangular garden

Perimeter of the garden = AB + BC + AC

Formula to get the distance between A and B,

d = $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

AB = $\sqrt{(0-6)^2+(6-5)^2}$ = $\sqrt{37}$

BC = $\sqrt{(6-5)^2+(5+1)^2}$ = $\sqrt{37}$

AC = $\sqrt{(0-5)^2+(6+1)^2}$ = $\sqrt{74}$

Perimeter = $\sqrt{37}+\sqrt{37}+\sqrt{74}$

= 6.08 + 6.08 + 8.60

= 20.76

≈ 20.8 units

Therefore, amount of fencing required to cover the triangular park is 20.8 units.

3 0

2 years ago

Write the function as an algebraic equation

Leto [7]

Answer:

OMGGGG WANNA WRK ON THIS TOGETHER I NEED THIS PROBLEM TOOOOO

4 0

2 years ago

Suppose that a college determines the following distribution for X = number of courses taken by a full-time student this semeste

lidiya [134]

Answer:

$E(X) = \sum_{i=1}^n X_i P(X_i) = 3*0.07 +4*0.4 +5*0.25 +6*0.28= 4.74$ In order to find the variance we need to calculate first the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 3^2*0.07 +4^2*0.4 +5^2*0.25 +6^2*0.28= 23.36$ And the variance is given by:

$Var(X) = E(X^2) +[E(X)]^2 = 23.36 -[4.74]^2 = 0.8924$

And the deviation would be:

$Sd(X) =\sqrt{0.8924} =0.9447$

Step-by-step explanation:

Previous concepts

The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.

The variance of a random variable X represent the spread of the possible values of the variable. The variance of X is written as Var(X).

Solution to the problem

For this case we have the following distribution given:

X 3 4 5 6

P(X) 0.07 0.4 0.25 0.28

We can calculate the mean with the following formula:

$E(X) = \sum_{i=1}^n X_i P(X_i) = 3*0.07 +4*0.4 +5*0.25 +6*0.28= 4.74$

In order to find the variance we need to calculate first the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 3^2*0.07 +4^2*0.4 +5^2*0.25 +6^2*0.28= 23.36$

And the variance is given by:

$Var(X) = E(X^2) +[E(X)]^2 = 23.36 -[4.74]^2 = 0.8924$

And the deviation would be:

$Sd(X) =\sqrt{0.8924} =0.9447$

3 0

3 years ago

17,358 divided blank equals 789

Otrada [13]

1= 22.08
2= 25704
3= 587
4= 610

6 0

2 years ago

What is the value of x?<br> 95<br> 57

Xelga [282]

Answer:

I think X is just the subtraction of the other angles

Step-by-step explanation:

x=95-57

X=38°

4 0

2 years ago

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