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professor190 [17]
3 years ago
7

The perimeter of a rectangular garden is 50 feet. Its width is 10 feet. What is the length of the garden?

Mathematics
1 answer:
luda_lava [24]3 years ago
4 0

Hey there! The equation for perimeter is 2L x 2W, or L + L + W + W.

If P is 50, and it's W is 10, then we can do 2(10) + 2L = 50. This, simplified, becomes 20 + 2L = 50. Subtract 20 on both sides, and you're left with 30.

The equation now becomes 2L = 30. Divide both sides by 2, and you're left with L = 15.

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Answer:

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Step-by-step explanation:

Given that,

Asn expression : (-27)^\dfrac{2}{3}

We need to evaluate the above expression.

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So,

(-27)^\dfrac{2}{3}=(-3)^{3\times \dfrac{2}{3}}

or

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No links or files, worth 25 points, please help!
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3 0
2 years ago
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A developer wants to enclose a rectangular grassy lot that borders a city street for parking. If the developer has 220 feet of f
MrRa [10]

Answer:

6050 square feet

Step-by-step explanation:

Based on the diagram attached, the area which the available fencing can enclose will measure X x Y feet. As the total length of fencing available is 220 feet, the fenced perimeter must equal 220 feet

Y + 2X = 220

Y = 220 - 2X

Area of a rectangle is determined by multiplying the length of perpendicular sides:

Area = X*Y

Area = X(220 - 2X)

Area = 220X - 2X^{2}

The derivative of an equation determines the slope at any given point of that equation. At the maximum or minimum point of the equation, the slope will be zero. Therefore, differentiating the equation for area and equating it to zero will give the value of X where the area is maximum.

A simple variable can be differentiated using below concept:

f(a) = a^{b}

f'(a) = ba^{b-1}

Using the above concepts to differentiate Area and calculate X will give:

Area = 220X - 2X^{2}

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Area = 55*110

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8 0
2 years ago
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