I need help with this please

What does the linear inequality y ≥ −x − 3 look like?

kupik [55]

It is a line that divides the space into two.. The line is y=-x-3

8 0

2 years ago

F(x)=2x-4. F(x)=2x-4 f-1x=_x+_. Complete the inverse function

natita [175]

Answer:

$f^{-1}(x) = \frac{1}{2}(x +4)$

Step-by-step explanation:

Given

$f(x) = 2x - 4$

Required

Determine the inverse function

Start by replacing f(x) with y

$y = 2x - 4$

Swap the positions of y and x

$x = 2y - 4$

Make y the subject: Add 4 to both sides

$x+4 = 2y - 4+4$

$x+4 = 2y$

Make y the subject: Divide through by 2

$\frac{1}{2}(x + 4) = y$

$y = \frac{1}{2}(x + 4)$

Replace y with f-1(x)

$f^{-1}(x) = \frac{1}{2}(x +4)$

3 0

2 years ago

A bottle is filled with saline solution for eyes, is the bottle more likely to hold 15 milliliters of solution or 1 liter of sol

Gnesinka [82]

The bottle is more likely to hold 15 milliliters

hope this helped

3 0

3 years ago

Can some help please

Katyanochek1 [597]

Answer:

Step-by-step explanation:

2 * 10^7 You are to use a single digit. That's the 2 on the left. Then count what it takes to get the decimal between the 2 and the 3. It's 7

0.000136

Count the number of zeros. Add a minus 1. You want the number to be counted until you get minus 1 which is the number of powers after the 1.

1 * 10^-4

26837 becomes 2 * 10^4. 4 is the number of digits you have before you get to a number between 1 and 10.

0.0302 becomes 3 * 10^-(1 + 1) = 3 * 10^-2

4 0

2 years ago

If f(x)=sinx 2x 1 and g is the inverse function of f

Bingel [31]

The value of the derivative of the function g(x) at x = 1 will be 1/3. Then the correct option is A.

<h3>What is an inverse function?</h3>

A function that may convert into another function is known as an inverse function or anti-function.

If the function is f(x) = sinx + 2x + 1.

Then the derivative of an inverse function g(x) of a function f(x) at a given value (a) will be

$\rm g'(a) = \dfrac{1}{f'(g(a))}$

The derivative of f(x) will be

f'(x) = cos x + 2

Then the given value of a will be

a = 1

g(x) = f⁻¹(x)

put x = 0, then we have

f(0) = sin 0 + 2(0) + 1

f(0) = 1

Put x = 1, in the function f⁻¹(x). Then we have

f⁻¹(1) = 0

and

g(1) = 0

Then put a = 1, then we have

$\rm g'(a) = \dfrac{1}{f'(g(a))}\\\\g'(1) = \dfrac{1}{f'(g(1))}\\\\g'(1) = \dfrac{1}{f'(0)}\\\\g'(1) = \dfrac{1}{\cos 0 + 2}\\\\g'(1) = \dfrac{1}{1+2}= \dfrac{1}{3}$

More about the inverse function link is given below.

brainly.com/question/2541698

#SPJ4

8 0

1 year ago