Is classified as a substance A. Elements and compound B.mixtures

emmainna [20.7K]

Gene therapy is designed to introduce genetic material into cells to compensate for abnormal genes or to make a beneficial protein. If a mutated gene causes a necessary protein to be faulty or missing, gene therapy may be able to introduce a normal copy of the gene to restore the function of the protein.

6 0

3 years ago

Which equation is used to help form the combined gas law? mc009-1. Jpg mc009-2. Jpg mc009-3. Jpg mc009-4. Jpg.

Luba_88 [7]

The combined gas law equation has been $\dfrac{P_1V_1}{T_1}=\dfrac{P_2V_2}{T_2}$ .

The combined gas law has been assigned to the ideal gas. It has been stating that ideal gas are having negligible inter-molecular attraction and collision resulting in the absence of pressure and volume from the particles.

In an ideal gas the equation has been given as:

$PV=nRT$

Where, P has been the pressure of the gas

V has been the volume of the gas

n has been the moles of the gas

R has been a constant

T has been the temperature of the gas

The combined gas law has been given as the change in the pressure, and volume for a gas. It has been given as:

$\dfrac{P_1V_1}{T_1}=\dfrac{P_2V_2}{T_2}$

For more information about combined gas law, refer to the link:

brainly.com/question/13154969

7 0

3 years ago

What is 0.00000005 in scientific notation, rounded to two significant figures?

KIM [24]

Answer:

5×-10^8

That is the the scintific notation for 0.00000005

Answer=5×-10^8

7 0

3 years ago

3. A 4.00 gram sample of solid gold was heated from 274K to 314K. How much energy was involved?

MrMuchimi

Q = mcΔT = (4.00 g)(0.129 J/g•°C)(40.85 °C - 0.85 °C)
Q = 20.6 J of energy was involved (more specifically, 20.6 J of heat energy was absorbed from the surroundings by the sample of solid gold).

3 0

3 years ago

Vitamin C, also known as ascorbic acid, is composed of 40.9 percent carbon, 4.6 percent hydrogen, and 54.5 percent oxygen. The m

Vladimir79 [104]

Answer:

Molecular formula is : C₆H₈O₆

Explanation:

40.9 % of C, 4.6 % of H, 54.5 % of O means that in 100 g of ascorbic acid, we have 40.9 g of C, 4.6 g of H and 54.5 g of O.

If 1 mol of ascorbic acid weighs 176 g, let's determine the rules of three to know the grams of each element:

100 g of compound has ___ 40.9 g C __ 4.6 g H ___ 54.5 g O

176 g compound mus have:

(176 . 40.9) / 100 = 72 g of C

(176 . 4.6) / 100 = 8 g of H

(176 . 54.5) / 100 = 96 g of O

If we convert the mass to moles:

72 g . 1 mol / 12 g = 6 C

8 g . 1 mol/ 1g = 8 H

96 g . 1mol / 16 g = 6 O

Molecular formula is : C₆H₈O₆

In conclussion, 1 mol of ascorbic acid has 6 moles of C, 8 moles of H and 6 moles of O

6 0

3 years ago