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Alinara [238K]
3 years ago
14

Problem PageQuestion While ethanol is produced naturally by fermentation, e.g. in beer- and wine-making, industrially it is synt

hesized by reacting ethylene with water vapor at elevated temperatures. A chemical engineer studying this reaction fills a tank with of ethylene gas and of water vapor. When the mixture has come to equilibrium he determines that it contains of ethylene gas and of water vapor. The engineer then adds another of ethylene, and allows the mixture to come to equilibrium again. Calculate the moles of ethanol after equilibrium is reached the second time. Round your answer to significant digits.

Chemistry
1 answer:
OverLord2011 [107]3 years ago
4 0

Question: The question is incomplete. Below is the complete question and the answer;

While ethanol (CH3CH2OH is produced naturally by fermentation, e.g. in beer- and wine-making, industrially it is synthesized by reacting ethylene CH2CH2) with water vapor at elevated temperatures. A chemical engineer studying this reaction fills a 50.0 L tank at 22. °C with 24. mol of ethylene gas and 24. mol of water vapor. He then raises the temperature considerably, and when the mixture has come to equilibrium determines that it contains 15.4 mol of ethylene gas and 15.4 mol of water vapor The engineer then adds another 12. mol of water, and allows the mixture to come to equilibrium again. Calculate the moles of ethanol after equilibrium is reached the second time. Round your answer to 2 significant digits.

Answer:

Number of moles of ethanol = 11 mol

Explanation:

SEE THE ATTACHED FILE FOR THE CALCULATION

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1. Consider the following: h2so4 2 naoh → na2so4 2 h2o if a 24. 0 ml sample of h2so4 (aq) was neutralized by 20. 0 ml of 0. 125
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The molarity of the acid sample H₂SO₄ is 0.052M .

<h3>What is Molarity ?</h3>

Molarity (M) is the amount of a substance in a certain volume of solution.

Molarity is defined as the moles of a solute per liters of a solution.

Molarity is also known as the molar concentration of a solution

Now to determine the molarity of the acid sample

V( H₂SO₄) = 24.0 mL in liters = 24.0 / 1000 = 0.024 L

M(H₂SO₄) = ?

V(NaOH) = 20.0 mL = 20.0 / 1000 = 0.02 L

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Number of moles NaOH :

n = M x V

n = 0.125 x  0.02

n = 0.0025 moles of NaOH

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1 mole H₂SO₄ ---------- 2 mole NaOH

? mole H₂SO₄ ---------- 0.0025 moles NaOH

moles = 0.0025 * 1 / 2

= 0.00125 moles of H₂SO₄

M(H₂SO₄) = n / V

M = 0.00125 /  0.024

= 0.052 M

Therefore the molarity of the acid sample H₂SO₄ is 0.052M .

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