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Elden [556K]
3 years ago
8

What are the periodic trends of ionic radii? Check all that apply.

Chemistry
2 answers:
Troyanec [42]3 years ago
6 0
Atomic radii increase when going down a group and decreases when going towards the anion periods. So A and D.
Goryan [66]3 years ago
4 0

Ionic radii tend to increase down a group, so A, cationic radii tend to decrease across a period, so D, Ionic radii increase when switching from cations to anions in a period, E.

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How many mL will a 0.205 mole sample of He occupy at 3.00 atm and 200 K? Report your answer to the nearest mL.
Tcecarenko [31]

1.1214 mL will a 0.205-mole sample of He occupy at 3.00 atm and 200 K.

<h3>What is an ideal gas equation?</h3>

The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

Using equation PV=nRT, where n is the moles and R is the gas constant. Then divide the given mass by the number of moles to get molar mass.

Given data:

P= 3.00 atm

V= ?

n=0.205 mole

R= 0.082057338 \;L \;atm \;K^{-1}mol^{-1}

T=200 K

Putting value in the given equation:

\frac{nRT}{P} =V

V= \frac{0.205 \;mole\;0.082057338 \;L \;atm \;K^{-1}mol^{-1} X 200}{3 \;atm}

V= 1.1214 mL

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4 0
2 years ago
If 16.5g of c6h14o2 are reacted vwith .499 mol of o2. How many moles of co2 should be produced
Fed [463]

Answer:

moles of carbon dioxide produced are 410.9 mol.

Explanation:

Given data:

Mass of C₆H₁₄O₂ = 16.5 g

Moles of O₂ = 499 mol

Moles of CO₂ = ?

First of all we will write the balance chemical equation.

2C₆H₁₄O₂  +  17O₂  →   14CO₂  +  12H₂O

moles of C₆H₁₄O₂  = mass × molar mass

moles of C₆H₁₄O₂ =  16.5 g × 118 g/mol

moles of C₆H₁₄O₂ = 1947 mol

Now we compare the moles of CO₂ with moles of O₂ and C₆H₁₄O₂ from balance chemical equation.

                 O₂      :     CO₂

                 17       :      14

                499     :      14/17× 499 = 410.9 moles

          C₆H₁₄O₂   :   CO₂

                    2    :      14

                 1947 :     14/2× 1947 =  13629 moles

Oxygen will be limiting reactant so moles of carbon dioxide produced are 410.9 mol.

5 0
3 years ago
Read 2 more answers
Combustion vapor-air mixtures are flammable over a limited range of concentrations. The minimum volume % of vapor that gives a c
DochEvi [55]
Combustion equation of n-hexane:

2C₆H₁₄ + 19O₂ → 12CO₂ + 14H₂O

a)
Assuming we have 100 moles of air,
Oxygen = 20.9 moles
n-hexane required = 20.9/19 x 2
= 2.2 moles

LFL = Half of stoichometric amount = 2.2 / 2 = 1.1
LFL n-hexane = 1.1% 

b)
1.1 volume percent required for LFL

1.1% x 1
= 0.0011 m³ of n-hexane required
6 0
3 years ago
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Louisa put a bowl of water and a bowl of sand in the sun. She put a thermometer in each bowl. Then she recorded the temperature
Helen [10]

The experiment that was carried out by Louisa goes to show us that different materials heat up at different rates.

<h3>What is the specific heat capacity?</h3>

The term specific heat capacity just goes to show us the amount of heat that must be absorbed before the temperature of an object would rise by 1 K. In this case, we can see that we have been told that the after 30 minutes, the sand had heated more than the water. This simply implies that the energy that the sand and the water absorbed was able to increase the temperature of the sand mush more than it increased the temperature of the water.

Thus we can see that the heat capacity of the sand is much less than the heat capacity of the water since the sand could be able to be heated up much faster than the the water could be heated up.

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8 0
1 year ago
A geologist is making observations from atop a small mountain. She sees two parallel faults: one directly to the east and one di
GenaCL600 [577]

Answer:

Fault-block mountain

Explanation:

I got it right on the assignment

3 0
3 years ago
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