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Arturiano [62]
3 years ago
6

HELP HELP HELP!! Explain the various factors that impact the solubility of substances in water.

Chemistry
2 answers:
astraxan [27]3 years ago
8 0

Answer:

1) Temperature

When salts like KNO3, NANO3 and KCl are added in water the test tube ecomes cold, which means the heat is being absorbed. Solubility usually increases with increase in temperature for such solutes.

On the other hand, when salts like Li2SO4 and Ce2(SO4)3 are dissolved in water, test tube turns warm which indicates the heat is released. In such cases the solubility of salt decreases with increase in temperature.

In some cases,the heat is neither absorbed nor releasedwhen dissolved in water. When salts like NaCl is added in water, the temperature remains the same, and hence temperature has minimal effect on solubility.

2) Pressure

The solubility of solid and liquids aren't affected by pressure but the solubility of gas in a liquid is directly propotional to the pressure of gas. This is also explained through Henry's Law. i.e.

m ∝ P or m = KP

where "m" is the amount of gas dissolved.

Hope that helps, it might be a little too detailed and lenthy, but it explains everything you asked.

Agata [3.3K]3 years ago
4 0

Explanation:

There are two direct factors that affect solubility: temperature and pressure. Temperature affects the solubility of both solids and gases, but pressure only affects the solubility of gases.

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Barium nitrate and sodium sulfate solutions can be used to precipitate barium sulfate. How many grams
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Answer:

40.8g of sodium sulfate must be added

Explanation:

The reaction of barium nitrate, Ba(NO₃)₂ with sodium sulfate, Na₂SO₄ is:

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That means, for a complete reaction of an amount of barium nitrate you must add the same amount in moles of sodium sulfate. To solve this problem we need to convert the mass of barium nitrate to moles = Moles of sodium sulfate that must be added:

<em>Moles Ba(NO₃)₂ -Molar mass: 261.3g/mol-:</em>

75g * (1mol / 261.3g) = 0.287 moles = Moles Na₂SO₄

<em>Mass Na₂SO₄ -Molar mass: 142.04g/mol-:</em>

0.287 moles * (142.04g / mol) =

<h3>40.8g of sodium sulfate must be added</h3>
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