Question

Some math problems so yep help pls

Answer 1

Answer:

Step-by-step explanation:

Take this one thing at a time...baby steps to help us keep our sanity. Math does tend to drive a person around the bend...

The first term is the tricky one. If the exponent is negative, it can be rewritten as a positive by putting whatever the exponent is on under a 1. For example:

$x^{-2}=\frac{1}{x^2}$

So we'll use that to make this simpler.

$(-\frac{1}{2})^{-2}=\frac{1}{(-\frac{1}{2})^2 } }$  Squaring that negative makes it a positive, so we can rewrite as

$\frac{1}{(\frac{1}{2})^2 }$ which simplifies to

$\frac{1}{\frac{1}{4} }$  What we have there is a fraction over a fraction; namely:

$\frac{\frac{1}{1} }{\frac{1}{4} }$ and the rule for that is to bring the bottom fraction up, flip it and multiply:

$\frac{1}{1}$ × $\frac{4}{1}$ which is 4.

Now for the second part. All we are doing here is squaring that fraction. Remember that squaring a negative makes it a positive, so

$(-\frac{1}{2})^2=\frac{1}{4}$ . Now we'll put these together to get the sum

$4+\frac{1}{4}$ and with a common denominator of 4, this becomes

$\frac{16}{4}+\frac{1}{4}$ and that equals

$\frac{17}{4}$, the seond choice down.