Answer:
W = 71J
Explanation:
Given force F = (5i+5j−1k)N
d = Δr
r1 = (−5,−3,−4)m
r2 = (2,5,0)m
Δr = r2 – r1 = (2-(-5), 5-(-3), 0-(-4))
Δr = (2+5, 5+3, 0+4) = (7i+ 8j +4k)m
W = F•d = (5i+5j−1k)•(7i+ 8j +4k)
W = 5×7 + 5×8 +-1×4 = 35 + 40 - 4
W = 71J
Answer:
I need help with the same question
Explanation:
Answer:
option E
Explanation:
given,
Parallax angle(d) = 1 arcsecond
using Parallax formula

p is the parsecs angle which is measured in 1 arcsecond
d is the distance in parsec
now,



we know,
1 parsec = 3.26 light year
hence, the answer will be option E
Answer:
The work done will be 
Explanation:
The work equation is given by:

Where:
F is the force due to gravity (weight = mg)
x is the length of the ramp (3 m)
Now, the force acting here is the component of weight in the ramp direction, so it will be:

Therefore, the work done will be:



I hope it helps you!
The first thing you should know is that the friction force is equal to the coefficient of friction due to normal force.
Therefore, clearing the normal force we have:
The friction is 565N.
(565 / 0.8) = 706.25N. weight.