Answer:
The magnitude of the horizontal displacement of the rock is 7.39 m/s.
Explanation:
Given that,
Initial speed = 11.5 m/s
Angle = 50.0
Height = 30.0 m
We need to calculate the horizontal displacement of the rock
Using formula of horizontal component
Put the value into the formula
Hence, The magnitude of the horizontal displacement of the rock is 7.39 m/s.
The best object to show the Earth's true appearance is something round and smooth. Since the earth is only slightly oblate, it doesn't matter based on its size, and you would use a pool ball as the perfect scale model, because it is very round and smooth.
Answer:
Log 10 ( 4.16x10^16)
Explanation:
Other distance from sun you have to search by your self then apply the equation Log 10 ( distance from sun )
I'm not sure but it might explode and make the wood catch fire
I'm going to assume this is over a horizontal distance. You know from Newton's Laws that F=ma --> a = F/m. You also know from your equations of linear motion that v^2=v0^2+2ad. Combining these two equations gives you v^2=v0^2+2(F/m)d. We can plug in the given values to get v^2=0^2+2(20/3)0.25. Solving for v we get v=1.82 m/s!
