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Marta_Voda [28]
2 years ago
11

The picture shows an aerialist walking on a tightrope and holding a balancing bar.

Physics
2 answers:
uysha [10]2 years ago
6 0
A. The aerialist’s feet and the rope
Stels [109]2 years ago
5 0

Answer:

the aerialist's feet and the rope is the answer.

Explanation:

Hope this helps!

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Which is an action/reaction force pair? check all that apply.
Vesna [10]

Answer:

According to Newton's third law, for every action force there is an equal (in size) and opposite (in direction) reaction force. Together, these two forces exerted upon two different objects form the action-reaction force pair.

Explanation:

Sana makatulong ^_^

3 0
2 years ago
Which of the following is a common downside of net pens, one of the most common forms of aquaculture?
Eduardwww [97]

Answer:

Answer is overcrowding aka answer choice A. I got the question and got it right. Please mark brainliest. Have a good day! :)

Explanation:

8 0
3 years ago
Read 2 more answers
A package of mass 5 kg sits on an airless asteroid of mass 7.6 × 1020 kg and radius 8.0 × 105 m. We want to launch the package i
Effectus [21]

Answer:

s =  1.7 m

Explanation:

from the question we are given the following:

Mass of package (m) = 5 kg

mass of the asteriod (M) = 7.6 x 10^{20} kg

radius = 8 x 10^5 m

velocity of package (v) = 170 m/s

spring constant (k) = 2.8 N/m

compression (s) = ?

Assuming that no non conservative force is acting on the system here, the initial and final energies of the system will be the same. Therefore  

• Ei = Ef

• Ei = energy in the spring + gravitational potential energy of the system

• Ei = \frac{1}{2}ks^{2} + \frac{GMm}{r}

• Ef = kinetic energy of the object

• Ef = \frac{1}{2}mv^{2}  

• \frac{1}{2}ks^{2} + (-\frac{GMm}{r}) = \frac{1}{2}mv^{2}  

• s = \sqrt{\frac{m}[k}(v^{2}+\frac{2GM}{r})}

s = \sqrt{\frac{5}[2.8 x 10^5}(170^{2}+\frac{2 x 6.67 x10^{-11} x 7.6 x 10^{20}}{8 x 10^5})}

s =  1.7 m

7 0
3 years ago
Who did not have experimental evidence to support his theory of the atom? Dalton Thomson Rutherford Democritus
Aloiza [94]

Democritus was the one who did not have experimental evidence to support his theory of the atom.

Answer: Option 4

<u>Explanation: </u>

The discovery of atoms were first stated by Democritus but due to the absence of any experimental proof, his statement was not noted as significant at that time.

After this, Dalton made the specific assumptions formulating some postulates for the atomic theory with proof. Then the cathode rays tube experiments performed by Thomson lead to the formation of plum pudding models of atom.

This is followed by Rutherford’s gold foil experiment discovering the presence of nucleus inside the atoms. So, Democritus first stated but due to absence of experimental evidences, his theory of atoms were not supported at that time.

3 0
3 years ago
In which part of the wave are the particles of the medium closer together?
Lesechka [4]
B.) Compressions 
HOPPE IT HELPED
6 0
3 years ago
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