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KiRa [710]
2 years ago
15

(GIVING BRAINLIEST!!)

Mathematics
1 answer:
Ira Lisetskai [31]2 years ago
6 0

Answer:

IT IS THE ANSWER B) SNOW

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What is its first derivative
agasfer [191]

Answer:

2ax + b + C

where C is a constant.

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2 years ago
Use the associative property to simplify the expression.
BaLLatris [955]

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through

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Barb solved the following equation: 4(3x – 12) = 5(2x + 6)
katrin2010 [14]

Answer:

4(3 * 39 – 12) = 5(2 * 39 + 6)

x = 39


Step-by-step explanation:

4(3x – 12) = 5(2x + 6)

(12x - 48) = (10x + 30)

12x - 10x = 30 + 48

2x = 78

2x/2 = x

78/2 = 39

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No Prob :)

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3 years ago
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Which equation has no solution?
Sergeu [11.5K]
Do each equation individually and compare if they are the same end answer in each question. which ever one is unequal than that is the answer
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2 years ago
Define fn : [0,1] --> R by the
sasho [114]

Answer:

The sequence of functions \{x^{n}\}_{n\in \mathbb{N}} converges to the function

f(x)=\begin{cases}0&0\leq x.

Step-by-step explanation:

The limit \lim_{n\to \infty }c^{n} exists and converges to zero whenever \lvert c \rvert. But, if c=1 the sequence \{c^{n}\} is constant and all its terms are equal to 1, then converges to 1. Using this result, consider the sequence of functions \{f_{n}\} defined on the interval [0,1] by f_{n}(x)=x^{n}. Then, for all 0\leq x we have that \lim_{n\to \infty}x^{n}=0. Now, if x=1, then \lim_{n\to \infty }x^{n}=1. Therefore, the limit function of the sequence of functions is

f(x)=\begin{cases}0&0\leq x.

To show that the convergence is not uniform consider 0. For any n>1 choose x\in (0,1)  such that \varepsilon^{1/n}. Then

\varepsilon

This implies that the convergence is not uniform.

8 0
3 years ago
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