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KiRa [710]
2 years ago
15

(GIVING BRAINLIEST!!)

Mathematics
1 answer:
Ira Lisetskai [31]2 years ago
6 0

Answer:

IT IS THE ANSWER B) SNOW

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3) x2+ y2 - x + 3y - 42 = 0<br> X+y=4
REY [17]

The solution is (-1,5) and (7,-3)

Step-by-step explanation:

The expression is x^{2} +y^{2} -x+3y-42=0 and x+y=4

Using substitution method we can solve the expression.

Let us substitute x=4-y in x^{2} +y^{2} -x+3y-42=0

(4-y)^{2} +y^{2} -(4-y)+3y-42=0

Expanding and simplifying the expression, we get,

\begin{array}{r}{16-8 y+y^{2}+y^{2}-4+y+3 y-42=0} \\{2 y^{2}-4 y-30=0}\end{array}

Let us use the quadratic equation formula to solve this equation,

\begin{aligned}y &=\frac{4 \pm \sqrt{16-4(2)(-30)}}{2(2)} \\&=\frac{4 \pm \sqrt{16+240}}{4} \\&=\frac{4 \pm 16}{4} \\y &=1 \pm 4\end{aligned}

Thus, y=5 and y=-3

Substituting y-values in the equation x+y=4, we get the value of x.

For y=5 ⇒ x=4-5=-1

For y=-3 ⇒ x=4+3=7

Thus, the solution set is (-1,5) and (7,-3)

7 0
3 years ago
Help me out please! i really need it
otez555 [7]

Answer:

x=14

Step-by-step explanation:

to find x you have to isolate it so you divide 3 by both sides and that leaves you with the answer

3 0
2 years ago
Read 2 more answers
Which of the following numbers can be expressed as repeating decimals? 3 over 7, 2 over 5, 3 over 4, 2 over 9
Maurinko [17]

Hello!

Let's think about the denominators we have. A seventh goes on forever in no specified order. A fifth an a fourth have set decimal values, 0.2 and 0.25, so they are not repeating decimals. A ninth is 0.111111..., it repeats like this forever in a specified order. Therefore, 2/9, or 0.222222...., would be a repeating decimal.

Therefore, our answer is \boxed {\frac{2}{9}}.

I hope this helps!

6 0
3 years ago
HELP ASAP!!!!!!!! PLSSSSSSS HURRY!!!
tamaranim1 [39]

Answer:

D

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
how many ways are there to adjust two quantities so that they are in a given proportional relationship? Explain your reasoning.
dolphi86 [110]
The question is, "how many ways ...". 

There are as many ways to solve a math problem as you can think of. (Some are shorter or easier than others.)

Essentially, an infinite number.
7 0
3 years ago
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