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kondaur [170]
3 years ago
9

Find the value of x. x = [?]

Mathematics
1 answer:
Nikolay [14]3 years ago
5 0

Answer:

16

Step-by-step explanation:

x=7-9

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Simplify the following expression by combining like terms.<br> 3x + 4x² - 7x+ 9x2
EleoNora [17]

Answer:

13x² - 4x

Step-by-step explanation:

3x + 4x² - 7x + 9x² ← collect like terms

= (4x² + 9x² ) + (3x - 7x)

= 13x² + (- 4x)

= 13x² - 4x

7 0
2 years ago
6. GODEEPER Anders makes 7 fruit cups. He puts 2 green
Pie

Answer:

42

Step-by-step explanation:

because 2+2+2=6×7=42

5 0
3 years ago
In AVWX, XV<br> W X and mW<br> - 27°. Find m_X.
SashulF [63]

Answer:

m<X = 126^{o}

Step-by-step explanation:

From the given isosceles triangle, we have;

<W and <V as the base angles

So that,

m<W = m<V = 27 (base angles of an isosceles triangle are equal)

Thus,

m<X + m<V + m<W = 180 (sum of angles in a triangle)

m<X + 27 + 27 = 180

m<X + 54 = 180

m<X = 180 - 54

       = 126

m<X = 126^{o}

8 0
2 years ago
2x + 3y = 12<br> Complete the missing value in the solution to the equation.<br> 1,8)
Free_Kalibri [48]

Answer:

Step-by-step explanation:

\mathrm{Slope-Intercept\:form\:of}\:2x+3y=12:\quad y=-\frac{2}{3}x+4\\\mathrm{Domain\:of\:}\:-\frac{2}{3}x+4\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-\infty \:

\mathrm{Parity\:of}\:-\frac{2}{3}x+4:\quad \mathrm{Neither\:even\:nor\:odd}\\\mathrm{Axis\:interception\:points\:of}\:-\frac{2}{3}x+4:\quad \mathrm{X\:Intercepts}:\:\left(6,\:0\right),\:\mathrm{Y\:Intercepts}:\:\left(0,\:4\right)\\\mathrm{Inverse\:of}\:-\frac{2}{3}x+4:\quad -\frac{3x-12}{2}\\\mathrm{Slope\:of\:}-\frac{2}{3}x+4:\quad m=-\frac{2}{3}

4 0
3 years ago
Read 2 more answers
What is the domain of the function y = 2 StartRoot x minus 5 EndRoot?
Juli2301 [7.4K]

Answer:

The domain of the function should be:

'x greater than or equal to negative -5'.

Hence, option A is true.

Step-by-step explanation:

Given the expression

2\sqrt{x-5}

The domain of a function is the set of input or arguments for which the function is real and defined

We know that the value, inside the radicand, is the number found inside a radical symbol which must be greater than 0, otherwise, it would make the function undefined,

i.e.

x-5 ≥ 0

x ≥ 5

In other words, the domain of the function should be:

'x greater than or equal to negative -5'.

Therefore, the domain of the function:

x ≥ 5

\mathrm{Domain\:of\:}\:2\sqrt{x-5}\::\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x\ge \:5\:\\ \:\mathrm{Interval\:Notation:}&\:[5,\:\infty \:)\end{bmatrix}

Hence, option A is true.

3 0
3 years ago
Read 2 more answers
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