Answer:
5.9125in^2
Step-by-step explanation:
Step one:
Given data
Dimension of square= 5.25 in
Area of sqaure= 5.25^2= 27.5625 in^2
We are told that the sides of the circle touch the sides of the square
hence the diameter of the circle is 5.25in
radius= 5.25/2= 2.625 in
Area of circle= πr^2
Area of circle = 3.142*2.625^2
Area of circle=3.142*6.890625
Area of circle= 21.65 in^2
Step two:
The area that is not inside the circle
=Area of square-Area of circle
=27.5625- 21.65
=5.9125in^2
Answer:
Step-by-step explanation:
I just finished this exam review and it should be f(x)=4(^3sqrt16)^2x
Hope this helps you out!
The relevant formula that we can use in this situation is:
v = v0 + at
where v is the final velocity, v0 is the initial velocity
= 20 km/hr, a is acceleration at 3.4 m/s^2 and t is time at 20 seconds
First convert v0 to m/s, v0 = 5.56 m/s
v = 5.56 m/s + 3.4 m/s^2 * 20 s
v = 73.56 m/s
Then convert back to km/hr:
<span>v = 264.82 km/hr</span>
