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Ivenika [448]
3 years ago
12

Help? I'd Appreciate it!

Mathematics
1 answer:
kondor19780726 [428]3 years ago
8 0

<u>Answer</u>

y = (1/2)x - 1


<u>Explanation</u>

The first step is to get the gradient of the line.

The two points in the line are; (2,0) and (-2, -2).

Gradient = (-2 - 0)/(-2, - 2)

                = -2/-4

                 = 1/2

To get the function we use one of the point (2,0) and a general point (x,y).

1/2 = (y - 0)/(x - 2)

1/2 = y/(x - 2)

(x - 2) = 2y

2y = x - 2

y = (1/2)x - 1

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What is the general form of the equation for the given circle centered at o (0,0) (4,5)?
charle [14.2K]
The general equation of the circle is expressed as (x-h)2 + (y-k)2 = r2 where (h,k) is the center of the circle. we are are given the center of the circle at (0,0) so the expression is simplified to <span>(x)2 + (y)2 = r2. given the other point, r2 is equal to 41. hence the final equation is x2 + y2 = 41</span>
8 0
3 years ago
Why is the equation y-y1=m(x-x1) called the point-slope form?
MatroZZZ [7]

Answer:

The equation of the line with slope m = 2 and passing through the point (1, 1) will be:

y = 2x

Step-by-step explanation:

We know that the point-slope form of the line equation is

y-y_1=m\left(x-x_1\right)

where

  • m is the slope of the line
  • (x₁, y₁) is the point

The formula y-y_1=m\left(x-x_1\right) is termed as the point-slope form of the line equation because if we know one point on a certain line and the slope of that line, then we can easily get the line equation with this formula and, hence, determine all other points on the line.

For example, if we are given the point (1, 1) and slope m = 2

Then substituting the values m = 2 and the point (1, 2)

y-y_1=m\left(x-x_1\right)

y - 2 = 2(x-1)

y - 2 = 2x-2

y = 2x-2+2

y = 2x

Therefore, the equation of the line with slope m = 2 and passing through the point (1, 1) will be:

y = 2x

5 0
2 years ago
(4+7 +5+5+2) +[14 5/8+ 14 3/4 +14 7/8+15 + 15 1/8]=​
Reptile [31]

Answer:

97 and 1/8

Step-by-step explanation:

(4 + 7 + 5 + 5 + 2) + (14 5/8 + 14 3/4 + 14 7/8 + 15 + 15 1/8)

23 + (14 5/8 + 14 3/4 + 14 7/8 + 15 + 15 1/8)

23 + 74 1/8

97 and 1/8

7 0
3 years ago
Read 2 more answers
What is the slope of a line that passes through the points (2,5) and (4,9)
ahrayia [7]

Answer:

2

Step-by-step explanation:

slope = difference of y/ difference of x

m = (9-5) / (4-2) = 4/2 = 2

8 0
3 years ago
The graph of a sinusoidal function intersects its midline at (0,5) and then has a maximum point at (\pi,6)
Natalija [7]
First, let's use the given information to determine the function's amplitude, midline, and period. 

Then, we should determine whether to use a sine or a cosine function, based on the point where x=0.

Finally, we should determine the parameters of the function's formula by considering all the above.
     
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The midline intersection is at y=5 so this is the midline. 

The maximum point is 1 unit above the midline, so the amplitude is 1. 

The maximum point is π units to the right of the midline intersection, so the period is 4 * π.
 
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Since the graph intersects its midline at x=0, we should use thesine function and not the cosine function. 

This means there's no horizontal shift, so the function is of the form -

a sin(bx)+d

Since the midline intersection at x=0 is followed by a maximumpoint, we know that a > 0.

The amplitude is 1, so |a| = 1. Since a >0 we can conclude that a=1. 

The midline is y=5, so d=5. 

The period is 4π so b = 2π / 4π = 1/2 simplified. 

f(x)1 sin   (\dfrac{1}{3}x) +5  = Solution
8 0
3 years ago
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