Reaction of Copper with Mercuric Nitrate is as follow,
Cu + Hg(NO₃)₂ → Cu(NO₃)₂ + Hg
According to equation,
1 Mole of Cu reacts to form = 1 Mole of Hg
So,
1.20 Moles of Cu will react to produce = X Moles of Hg
Solving for X,
X = (1.20 mol × 1 mol) ÷ 1 mol
X = 1.20 mol of Hg
Result:
1.20 mole of Cu when reacted with mercuric nitrate produces 1.20 moles of Hg.
Answer:
80.13g of SO2
Explanation:
4FeS2 + 11O2 —> 2Fe2O3 + 8SO2
Molar Mass of FeS2 = 55.8 + (2x32) = 119.8g/mol
Mass of FeS2 from the balanced equation = 4 x 119.8 = 479.2
Molar Mass of SO2 = 32 + (16x2) = 32 + 32 = 64g/mol
Mass of SO2 from the balanced equation = 8 x 64 = 512g
From the equation,
479.2g of FeS2 produced 512g of SO2.
Therefore, 75g of FeS2 will produce = (75 x 512)/479.2 = 80.13g of SO2
Visible light is the wave and it has 10^-6
The age of the fossil given the present amount of Carbon-14 is given in the equation,
A(t) = A(o)(0.5)^t/h
where A(t) is the current amount, A(o) is the initial amount, t is time and h is the half-life. Substituting the known values to the equation,
A(t) / A(o) = 0.125 = (0.5)^(t/5730)
The value of t from the equation is 17190.
Thus, the age of the fossil is mostly likely to be 17190 years old.
Answer:
pH= 0.92
Explanation:
HNO3-> H^+ +NO3^-
HNO3 is a strong acid, so it fully dissociates
[HNO3] = 0.12M [H^+] = 0.12M
pH= -log[H^+]
pH=-log[.12] = 0.92
pH = 0.92