Assuming ammonia is the product of this reaction:
N2+3H2--->2NH3
2 mole N2 * (3 mol H2)/(1 mol N2)= 6 mol H2
You would need 6 mol of hydrogen gas to completely react with 2 mol of nitrogen.
Answer:
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Answer: Thus molarity of is 1.35 M
Explanation:
To calculate the volume of acid, we use the equation given by neutralization reaction:
where,
are the n-factor, molarity and volume of acid which is
are the n-factor, molarity and volume of base which is KOH.
We are given:
Putting values in above equation, we get:
Thus molarity of is 1.35 M