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sergiy2304 [10]
3 years ago
15

If we reverse the reaction to read Z + W -> X + Y, the +deltaH would be a -delta H. Does this indicate that heat is given off

or absorbed in the reverse reaction

Chemistry
1 answer:
Gre4nikov [31]3 years ago
5 0

Answer:

<u>In this reaction heat is released</u>

Explanation:

Exothemic Reactions : Those reactions in which heat is released when the products are  formed .

For such reaction The enthalpy change is negative.

\Delta H= - for exothermic reaction

Endothermic Reactions : Those reaction which proceed by absorbing heat . Here heat is absorbed. The enthalpy change for such reactions is positive.

\Delta H= +

When the direction of reaction reverses , the value of H also changes.

In the given reaction,

X + Y\rightarrow Z +Q

\Delta H= +  = heat is absorbed

So,

Z+Q\rightarrow X+Y

\Delta H= - = heat is<u> released</u>

<u></u>

<u>E</u><em>xothermic reactions are more spontaneous as compared to endothermic ractions. This means that they  proceed own their own . Only little amount of energy is supplied to exothermic reaction to produce the prodct.</em>

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Choose the products that complete the reaction . The chemical equation may not be balanced . Al+H 2 SO 4 ? Al 2 (SO 4 ) 3 +H 2 O
alexandr402 [8]

Answer: Al2 (SO4)3 + H2

Explanation:

option C

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The Old Man in the Mountain was a natural rock formation in a cliff in the White Mountain in New Hampshire that became a symbol
Mashcka [7]

Answer: snow

Explanation:

On May 2, 2003, the Old Man of the Mountain, New Hampshire's famous face-shaped granite formation, adorned the side of Cannon Mountain in Franconia Notch State Park, just as it had for millennia. But by the next morning, it was gone: The iconic stone face had fallen.

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2 years ago
Part 1. Determine the molar mass of a 0.622-gram sample of gas having a volume of 2.4 L at 287 K and 0.850 atm. Show your work.
zaharov [31]

If a sample of gas is a 0.622-gram, volume of 2.4 L at 287 K and 0.850 atm. Then the molar mass of the gas is 7.18 g/mol

<h3>What is an ideal gas equation?</h3>

The ideal gas law (PV = nRT) relates to the macroscopic properties of ideal gases.

An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

Given :

  • V = 2.4 L = 0.0024
  • P = 86126.25 Pa
  • T =  287 K
  • m = 0.622
  • R = 8.314

The ideal gas equation is given below.

n = PV/RT

n = 86126.25 x 0.0024 / 8.314 x 287

n = 0.622 / molar mass (n = Avogardos number)

Molar mass =  7.18 g

Hence, the molar mass of a 0.622-gram sample of gas having a volume of 2.4 L at 287 K and 0.850 atm is 7.18 g

More about the ideal gas equation link is given below.

brainly.com/question/4147359

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4 0
1 year ago
For 2,663 kg of a compound with the formula Al(SO), determine the following quantities (4 pts each); a) The number of moles of t
Nastasia [14]

Answer:

a) 35.485 moles of Al(SO)

b) 35.485 moles of S atoms

c) 2.136197(10^{25}) Al atoms

d) 567.723 g of O

Explanation:

Let's define the following terms :

1 mol = 6.02.(10^{23}) elemental units

For example :

1 mol of oxygen atoms = 6.02.(10^{23}) oxygen atoms

Now, our compound has the following formula

Al(SO)

Where Al is aluminium

S is sulfur

And O is oxygen

All the subscripts are 1 so we can say the following :

1 molecule of Al(SO) has 1 atom of Al , 1 atom of S and 1 atom of O

In terms of moles :

1 mol of Al(SO) has 1 mol of Al , 1 mol of S and 1 mol of O

The molar masses of Al, S and O are

molarmass_{(Al)}=26.982\frac{g}{mol}

molarmass_{(S)}=32.065 \frac{g}{mol}

molarmass_{(O)}=15.999\frac{g}{mol}

If we sum all the molar masses =(26.982+32.065+15.999)\frac{g}{mol}=75.046\frac{g}{mol}

Finally, 75.046 g of Al(S0) is 1 mol of Al(SO) which contains 26.982 g of Al, 32.065 g of S and 15.999 g of O.

1 mol of Al(SO) contains 1 mol of Al, 1 mol of S and 1 mol of O.

Now we can calculate a),b),c) and d)

For a)

2.663 kg=2663g

75.046 g of Al(SO) = 1 mol of Al(SO)

2663 g of Al(SO) = x

x=\frac{2663}{75.046}mol=35.485 mol

2.663 kg of Al(SO) contains 35.485 moles of Al(SO)

b) and c) 1 mol of Al(SO) molecules contains 1 mol of S atoms and 1 mol of Al atoms

We have 35.485 moles of Al(SO) molecules so

We have 35.485 moles of S atoms

And 35.485 moles of Al atoms

If 1 mol = 6.02(10^{23})

35.485 moles of Al have (35.485)(6.02)(10^{23})=2.136197(10^{25}) Al atoms

d) 75.046 g of Al(SO) contains 15.999 g of O

2663 g of Al(SO) contains x g of O

x=\frac{(2663).(15.999)}{75.046} g

x = 567.723 g of O

6 0
3 years ago
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