Answer:
D.
Explanation:
In Chemistry, electrons can be defined as subatomic particles that are negatively charged and as such has a magnitude of -1.
Valence electrons can be defined as the number of electrons present in the outermost shell of an atom. Valence electrons are used to determine whether an atom or group of elements found in a periodic table can bond with others. Thus, this property is typically used to determine the chemical properties of elements.
Oxygen has a total number of eight (8) electrons and as such the is able to gain (receive) two (2) more electrons in order to have the same electron arrangements as the noble gas i.e an atom of neon that has a total number of ten (10) electrons.
Hence, contains the same number of electrons as an atom of neon.
The volume of 0.555M KNO3 solution would contain 12.5 g of solute iss 223 mL.
<h3>What is the relationship between mass of solute and concentration of solution?</h3>
The mass of solute in a given volume of solution is related by the formula below:
- Molarity = mass/(molar mass * volume)
Therefore, volume of solution is given by:
Volume = Mass /molarity * molar mass
Molar mass of KNO₃ = 101 g/mol
Volume = 12.5/(0.555 * 101)
Volume = 0.223 L or 223 mL
In conclusion, the volume of the solution is obtained from the molarity of solution as well as mass and molar mass of solute.
Learn more about molarity and volume at: brainly.com/question/26873446
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Answer:
787.5 grams of glucose (C₆H₁₂O₆) can prepare 1750 mL of a 2.50 M solution
Explanation:
Molarity (M) is a concentration measure that indicates the number of moles of solute that are dissolved in a given volume.
Molarity is expressed in the following way:
Molarity is expressed in units .
2.50 M means that in 1 L of solution there are 2.5 moles of glucose. So, you apply a rule of three as follows: if in 1 L there are 2.5 moles of glucose, in 1.75 L (1750 mL, being 1000 mL = 1 L) how many moles of the compound are there?
moles=4.375
Being:
- C: 12 g/mole
- H: 1 g/mole
- O: 16 g/mole
The molar mass of glucose is:
C₆H₁₂O₆= 6* 12 g/mole+ 12* 1 g/mole + 6* 16 g/mole
C₆H₁₂O₆= 180 g/mole
Then you can apply a rule of three as follows, knowing the moles in 1750 mL and the molar mass: if there are 180 g of glucose in 1 mole, how much mass is there in 4.375 moles?
mass= 787.5 g
<u><em>787.5 grams of glucose (C₆H₁₂O₆) can prepare 1750 mL of a 2.50 M solution</em></u>
If the American system is the same, group on should be alkali metals and the answer would be frankium
Answer:
Strong acids ionize completely in aqueous solutions while weak acids release a few ions in aqueous solutions.