Nathaniel has $2 worth of dimes and quarters. He has 6 more dimes than quarters. By following the steps below, determine the num
ber of dimes,x, and the number of quarters,y, that Nathaniel has.
Determine three ways to have 6 more dimes than quarters:
1 answer:
Answer:
Step-by-step explanation:
- Number of dimes = d, each d = 10 c
- Number of quarters = q, each q = 25 c
- Total = $2 = 200 c
<u>Equations according the given:</u>
<u>Solve for q by substitution:</u>
- 10(q + 6) + 25q = 200
- 10q + 60 + 25q = 200
- 35q = 140
- q = 140/35
- q = 4
<u>Find the value of d:</u>
Nathaniel has 10 dimes and 4 quarters
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Step-by-step explanation:
Answer:
x = .5
Step-by-step explanation:
4 / x = 8
4 / .5 = 8
x = .5
