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babunello [35]
3 years ago
15

Nathaniel has $2 worth of dimes and quarters. He has 6 more dimes than quarters. By following the steps below, determine the num

ber of dimes,x, and the number of quarters,y, that Nathaniel has.
Determine three ways to have 6 more dimes than quarters:
Mathematics
1 answer:
Aleksandr-060686 [28]3 years ago
8 0

Answer:

  • 10 dimes and 4 quarters

Step-by-step explanation:

  • Number of dimes = d, each d = 10 c
  • Number of quarters = q, each q = 25 c
  • Total = $2 = 200 c

<u>Equations according the given:</u>

  • 10d + 25q = 200
  • d = q + 6

<u>Solve for q by substitution:</u>

  • 10(q + 6) + 25q = 200
  • 10q + 60 + 25q = 200
  • 35q = 140
  • q = 140/35
  • q = 4

<u>Find the value of d:</u>

  • d = 4 + 6 = 10

Nathaniel has 10 dimes and 4 quarters

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  • Converse = "If corresponding angles are equal, then two lines are parallel"
  • Result = True

Explanation:

Refer to the converse of the corresponding angles theorem. The original version is stated as part A, and the converse is marked in bold above.

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The converse of "if P, then Q" is "If Q, then P". We swap the positions of P and Q. Do not negate either piece.

========================================================

Part B

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Recall that for any triangle, the three interior or inside angles always add to 180 degrees. In short: A+B+C = 180. If C = 70, then A+B = 180-C leads to A+B = 180-70 and A+B = 110. This process can be reversed.

========================================================

Part C

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