One number is 26 the other is 23
x+y=49
Y=x+3,X (now substitute it in the equation)
x+3+x=49
2x+3=49
2x=46. X=23
Y=x+3. Y=23+3 =26 for checking 23+26=49
It is 16 because 3x16=48 and 4x16=64!
Polynomial requirements
1. never divide by a placeholder
2. variable exponent has to be a whole number
3. can't have infinte terms
by 1. we eliinate 2nd one
by 2. we eliminate first one (√x=x^1/2) and 3rd one because it has an exponent in placeholder
thie leaves us with last one
f(x)=2x³-5x⁵-(2/9)x²+9
last one is answer
Answer:
-10/3 or -3.33
Step-by-step explanation:
substitute 0 for y
0 = 6x + 20
-20 = 6x + 20 - 20 subtract 20 on both sides
-20 = 6x divide by 6 on each side
-20/6 = 6x/6
x = -20/6 simplify
x = -10/3
Answer:
Step-by-step explanation:
d + q = 94.....d = 94 - q
0.10d + 0.25q = 19.30
0.10(94 - q) + 0.25q = 19.30
9.4 - 0.10q + 0.25q = 19.30
-0.10q + 0.25q = 19.30 - 9.40
0.15q = 9.90
q = 9.90/0.15
q = 66 <===== there are 66 quarters
d + q = 94
d + 66 = 94
d = 94 - 66
d = 28 <==== there are 28 dimes
