It will be 14.
i’ll attach an image to show work
Answer:
Step-by-step explanation:
I will help you just tell me what grade your in and i will help
Answer:
It can be determined if a quadratic function given in standard form has a minimum or maximum value from the sign of the coefficient "a" of the function. A positive value of "a" indicates the presence of a minimum point while a negative value of "a" indicates the presence of a maximum point
Step-by-step explanation:
The function that describes a parabola is a quadratic function
The standard form of a quadratic function is given as follows;
f(x) = a·(x - h)² + k, where "a" ≠ 0
When the value of part of the function a·x² after expansion is responsible for the curved shape of the function and the sign of the constant "a", determines weather the the curve opens up or is "u-shaped" or opens down or is "n-shaped"
When "a" is negative, the parabola downwards, thereby having a n-shape and therefore it has a maximum point (maximum value of the y-coordinate) at the top of the curve
When "a" is positive, the parabola opens upwards having a "u-shape" and therefore, has a minimum point (minimum value of the y-coordinate) at the top of the curve.
The answer is 14/3 or 4 and 2 thirds
Step-by-step explanation:
The x-intercept is at (-3, 0). To find the slope of the perpendicular line, let's rewrite the equation to its slope-intercept form, which is
y = (2/3)x + 2
This means that the perpendicular line has a slope m = -3/2. So the slope-intercept form of this new line is
y = -(3/2)x + k. Since this line passes through (-3, 0), we cal solve for k:
0 = -(3/2)(-3) + k or k = -9/2
So our equation becomes (slope-intercept form)
or in its standard form,
