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Blababa [14]
2 years ago
16

Which description of the graph of the linear inequality y > 3x – 8 is correct?

Mathematics
1 answer:
Umnica [9.8K]2 years ago
9 0

Options :

A.The graph will be a dashed line with a y-intercept of negative eight and a slope of three. The graph will be shaded below the line

B.The graph will be a solid line with a y-intercept of three and a slope of negative eight. The graph will be shaded above the line.

C. The graph will be a solid line with a y-intercept of three and a slope of negative eight. The graph will be shaded below the line.

D.The graph will be a dashed line with a y-intercept of negative eight and a slope of three. The graph will be shaded above the line

Answer:

D.The graph will be a dashed line with a y-intercept of negative eight and a slope of three. The graph will be shaded above the line

Step-by-step explanation:

The equation y > 3x – 8

Interpreting as a linear relation :

y > ax + b

Where, a = slope ; b = intercept

a = 3 ; that is a slope value of 3

b = -8 ; that is an intercept value of - 8

Since the inequality is >, a dashed line is used (dashed like is used for > and <) ; since we a have a greater than sign, the graph will be shaded above the dashed line.

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Answer:

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The side of one square is equal to 3m and its diagonal is equal to the side of a second square. Find the diagonal of the second
navik [9.2K]

Answer:

6m

Step-by-step explanation:

the side of first square = 3 m

area of first square = 3^2= 9 m^2

let the side of second square = x m

since diagonal of first square = x m as per the question

in a square each angle is 90 degree

therefore by applying pythagorus theorem ,

diagonal ^2 = side^2 + side ^2

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DIAGONAL= square root of 18

diagonal= 3\sqrt{2} m = side of second square

therefore in second square ,

one angle is 90  degree , therefore by applying pythagorue theorem

diaqonal^2 = side ^2 + side ^2 = (3\sqrt{2})^2 + ( 3\sqrt{2})^2

diagonal ^2 = 18 + 18

diagonal = square root of 36

therefore diagonal of second square is 6m

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8 0
3 years ago
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Find the area under the standard normal curve to the left of z=1.25.
snow_tiger [21]

For quite some time now, calculators have had statistical functions built in.  Here we need to use the stat. function normalcdf, which has only two inputs when we're working with z scores instead of raw scores.

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You wish to compare the prices of apartments in two neighboring towns. You take a simple random sample of 12 apartments in town
Rom4ik [11]

Answer:

The value of P-value is 0.0472.

Step-by-step explanation:

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Let \mu_1 = <u><em>true average price of apartments in town A</em></u>

\mu_2 = <u><em>true average price of apartments in town B</em></u>

So, Null Hypothesis, H_0 : \mu_1=\mu_2

Alternate Hypothesis, H_A : \mu_1\neq \mu_2  

The test statistics that have been used here is <u>two-sample t-test statistics</u>, i.e;

The test statistics given to us is 2.1

Now, the P-value of the test statistics is given by the following formula;

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Hence, the value of the p-value is 0.0472.

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