2700 bc in everminutes he would run 920
Answer:
64%
Step-by-step explanation:
divide 80 by 125 and get .64
Answer: The answer is x >7
Step-by-step explanation:
56⋅x>616−224
56⋅x>616-224
Simplify :
56⋅x>392
56⋅x>392
Dividing by the variable coefficient :
x>
392
56
x>39256
Simplify :
x>7
x>7
Inequality
56⋅x+224>616
56⋅x+224>616
is true for
x>7
x>7
Start circle: πd = (3.14)(19) = 59.7
Move diagonally to the circle with the radius of 6.2.
Second circle: 2πr = 2(3.14)(6.2) = 39
Move upwards to the circle with the radius of 10.5
third circle: 2πr = 2(3.14)(10.5) = 66
Move right to the circle with the diameter of 16.6
Fourth circle: πd = (3.14)(16.6) = 52.2
Move down to the circle with the diameter of 7.7
fifth circle: πd = (3.14)(7.7) = 24.2
Move down to the circle with the diameter of 50
Sixth circle: πd = (3.14)(50) = 157.1
Move left to the circle with the radius of 11.8
Seventh circle: 2πr = 2(3.14)(11.8) = 74.1
Move down to the circle with the radius of 38
Eight circle: 2πr = 2(3.14)(38) = 238.8
Move right to the circle with the diameter of 1.1
ninth circle: πd = (3.14)(1.1) = 3.5
Move right to the circle with the radius of 14.8
10th circle = 2πr = 2(3.14)(14.8) = 93
Move up to the end.
Hope this helps :)
Answer:
5(1248 lb/horse + t lb) ≤ 8000 lb
Step-by-step explanation:
One way to do this is to find the average weight of the 5 horses:
It is:
6,240 lb
---------------- = 1248 lb/horse
5 horses
and to this, for each horse, we must add t lbs tack.
Thus, 5(1248 lb/horse + t lb) ≤ 8000 lb
would be an appropriate inequality.
Please note that your question mentions "the following inequalities;" that means you are expected to share them! Please do so next time. Thanks.
