−0.2(3p−0.9)+0.4(−0.9p−5)

Mathematics

1 answer:

abruzzese [7]3 years ago

8 0

Answer:

-0.96p-2.18

Step-by-step explanation:

-0.2*3p=-0.6p and -0.2*0.9=-0.18

-0.6p-0.18+0.4(-0.9p-5)

0.4*-0.9p= -0.36p and 0.4*-5=-2

-0.6p-0.18-0.36p-2

-0.6p-0.36p=-0.96

-0.96p-0.18-2

-0.18-2=-2.18

-0.96p-2.18

hope this helps. Happy Holidays!!

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$\displaystyle{1.) \ \ f(x) = \dfrac{2}{3}x-8}\\\\\displaystyle{2.) \ \ f(x) = -4x+11}$

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<h3>
What is Range?</h3>

- Range is a set of all y-values in a set of coordinate points.

<h3>
Consider This:</h3>

A linear equation or function always have range equal to set of real number because you can substitute f(x) as any numbers and you'll still be able to solve for x-variable.

An quadratic equation or function may have range equal to set of positive real number or negative real number depending whether if the coefficient of x² is in positive or negative but consider this:

Suppose we have f(x) = x², f(x) cannot be negative number because that'd make the equation not real. Therefore, a quadratic function does not have $\displaystyle{\mathbb{R}}$ range.

For an exponential function, it's same as quadratic equation. It depends whether if a base is in negative or positive. You can consider like this:

Suppose we have $\displaystyle{f(x)=2^x}$ , f(x) cannot be negative number because there are no x-values that make the equation true. Therefore, an exponential function does not have $\displaystyle{\mathbb{R}}$ range as well.