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Marina86 [1]
3 years ago
6

A group of 19 students and adults went to the museum. The ticket price

Mathematics
1 answer:
stiv31 [10]3 years ago
6 0

Answer:

7 adults, 12 students

Step-by-step explanation:

10 20 30 40 50

60 70

74 78 82 86 90

94 98 102 106 110 114 118

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the city park department is planning to enclose a play aea. one side of the area will be against an existing building, so no fen
SVEN [57.7K]

Answer:

length = 200 m

width = 400 m

Step-by-step explanation:

Let the length of the plaing area is L and the width of the playing area is W.

Length of fencing around three sides = 2 L + W = 800

W = 800 - 2L ..... (1)

Let A is the area of playing area

A = L x W

A = L (800 - 2L)

A = 800 L - 2L²

Differentiate with respect to L.

dA/dL = 800 - 4 L

It is equal to zero for maxima and minima

800 - 4 L = 0

L = 200 m

W = 800 - 2 x 200 = 400 m

So, the area is maximum if the length is 200 m and the width is 400 m.

8 0
3 years ago
Read 2 more answers
Complete the table of values for the equation y = 3x + 5.
cricket20 [7]

f(x)=3x+5

f(-2)=3×(-2)+5

= -6+5

=-1

f(-1)=3×(-1)+5

=-3+5

=2

f(0)=3×0+5

=0+5

=5

f(1)=3×1+5

=3+5

=8

f(2)=3×2+5

=6+5

=11

3 0
2 years ago
the price of a technology stock was $9.53 yesterday. Today, the price rose to $9.66. Find the percentage increase. Round your an
galben [10]
So, 9.66 - 9.53 will then be 0.13, so if we take 9.66 to be the 100%, what is 0.13 off of it in percentage then?

\bf \begin{array}{ccll}
amount&\%\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
9.66&100\\
0.13&p
\end{array}\implies \cfrac{9.66}{0.13}=\cfrac{100}{p}\implies p=\cfrac{0.13\cdot 100}{9.66}
6 0
3 years ago
Factor the expression over the complex numbers. x^2 + 72
Ivan
No solution simply because the expression cannot be solved with rational numbers
7 0
3 years ago
Slove algebraically<br><br>3x - 4y = -24<br>x +4y=8<br>​
Vanyuwa [196]

Solve algebrically 3x - 4y = -24 and x + 4y = 8 is x = -4 and y = 3

<u>Solution:</u>

We have been given two equations which are as follows:

3x - 4y = -24   ----- eqn 1

x + 4y = 8   -------- eqn 2              

We have been asked to solve the equations which means we have to find the value of ‘x’ and ‘y’.

We rearrange eqn 2 as follows:

x + 4y = 8

x = 8 - 4y  ------eqn 3

Now we substitute eqn 3 in eqn 1 as follows:

3(8 - 4y) -4y = -24

24 - 12y - 4y = -24

-16y = -48

y = 3

Substitute "y" value in eqn 3. Therefore the value of ‘x’ becomes:

x = 8 - 4(3)

x = 8 - 12  = -4

Hence on solving both the given equations we get the value of x and y as -4 and 3 respectively.

5 0
3 years ago
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