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dybincka [34]
3 years ago
9

NEED HELP ASAP PLEASE!!

Mathematics
2 answers:
Aliun [14]3 years ago
8 0

Answer:

7√8

Step-by-step explanation:

Because You Add Two And Five

Maru [420]3 years ago
7 0

Answer:

I think the answer is 56 inches

Step-by-step explanation:

You might be interested in
PLEASE HELPPP!!!
Tems11 [23]

Answer:

a) -16t^{2}+64t\geq40

b)[2-\frac{\sqrt{6}}{2} , 2+\frac{\sqrt{6}}{2}]

(see attached picture for the number line)

This interval means that from about 0.78s to about 3.22s the ball will not be visible because it will be higher than 40 feet high.

c) h_{max}=64ft

d) t=2s

Step-by-step explanation:

a)

Basically the ball will disappear when it is higher than 40 ft, so we can build the inequality like this:

-16t^{2}+64t\geq40

this is because the function represents it's height, so when the function is greater than or equal to 40, then the ball will disappear.

b) to solve the inequality, first we need to turn the ≥ symbol to an = symbol and solve for t, so we get:

-16t^{2}+64t =40

we can move the 40 to the other side of the equation so we get:

-16t^{2}+64t-40=0

we can factor the equation so it's easier to solve, so we get:

-8(2t^{2}-8t+5) =0

which simplifies to:

2t^{2}-8t+5=0

and we can use the quadratic formula to solve this equation, so we get:

t=\frac{-b\pm\sqrt{b^{2}-4ac}}{2a}

so we get:

t=\frac{-(-8)\pm\sqrt{(-8)^{2}-4(2)(5)}}{2(2)}

which yields:

2\pm \frac{\sqrt{6}}{2}

and next we need to test the posible intervals to see which one makes the inequality true, the possible intervals are:

(-\infty, 2-\frac{\sqrt{6}}{2}]  for a test value of 0

[2-\frac{\sqrt{6}}{2},2+\frac{\sqrt{6}}{2}] for a test value of 1

[2+\frac{\sqrt{6}}{2},\infty) for a test value of 4

so next we test each of the values in the original inequality and see if the inequality is true:

(-\infty, 2-\frac{\sqrt{6}}{2}] for a test value of 0

-16(0)^{2}+64(0)\geq40

0\geq40 false

so this is not an answer.

[2-\frac{\sqrt{6}}{2},2+\frac{\sqrt{6}}{2}] for a test value of 1

-16(1)^{2}+64(1)\geq40

48\geq40

true, so this is an answer.

[2+\frac{\sqrt{6}}{2}, \infty) for a test value of 4

-16(4)^{2}+64(4)\geq40

-16(16)+64(4)\geq40

-256+256\geq40

0\geq40

false, so this is no answer.

So the answer is the interval:

[2-\frac{\sqrt{6}}{2},2+\frac{\sqrt{6}}{2}]

This interval means that from about 0.78s to about 3.22s the ball will not be visible because it will be higher than 40 feet high.

c) In order to find how high Penelope kick the football, we must find the vertex of the parabola which is gotten when graping the given function (see attached picture)

so we can use the following formula to find the t-value for this maximum height:

t=-\frac{b}{2a}

so we substitute the corresponding values:

t=-\frac{64}{2(-16)}

which yields:

t=2s

next, we can substitute this time into the original function to find the maximum height, so we get:

h=-16(2)^{2}+64(2)

which yields:

h=64 ft

d) We found the answer for d on the previous part where we got that t=2s

6 0
3 years ago
Multi step equation that equals -1
Vitek1552 [10]

5(x + 3) - 3(x - 2) = 19      That should give you the result you need. The answer will come out to be x = - 1

If you want it to be - 1 to start with, then

2(5x + 3) - 13x + 2 = - 1

7 0
3 years ago
There are red and blue balls in a bag. The number of blue balls is 27 and the red balls are 4/ 7 of all balls. What is the total
aliina [53]
<h3>♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>

➷ We know this:

3/7 = 27

You need to find the value of 1/7

To do this, divide by 3

27/3 = 9

1/7 = 9

Multiply this by 7 to get the total number of balls:

9 x 7 = 63

There are 63 balls.

<h3><u>✽</u></h3>

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

7 0
3 years ago
Given:
Fynjy0 [20]

Answer:

Option B is correct.

\triangle RST \cong \triangle TUR  

Step-by-step explanation:

Given: RSTU is a parallelogram.

By definition of parallelogram, two pairs of opposite sides are congruent in length.

⇒TU \cong RS and TS \cong RU

In triangle RST and  triangle TUR

RS \cong TU  [Side]  

TS \cong RU  [Side]

RT \cong RT   [Common side]

SSS(Side-Side-Side) postulates states that if three sides of one triangle are congruent to three sides of other triangle, then the triangles are congruent.

then, by SSS postulates we have;

\triangle RST \cong \triangle TUR    


5 0
4 years ago
The parabola x = y² - 9 opens:
irinina [24]
This is what it looks like. It opens to the right.

8 0
4 years ago
Read 2 more answers
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