Answer:
-12.5
Step-by-step explanation:
Hope it helps u
FOLLOW MY ACCOUNT PLS PLS
Answer:
Recall that a relation is an <em>equivalence relation</em> if and only if is symmetric, reflexive and transitive. In order to simplify the notation we will use A↔B when A is in relation with B.
<em>Reflexive: </em>We need to prove that A↔A. Let us write J for the identity matrix and recall that J is invertible. Notice that 
. Thus, A↔A.
<em>Symmetric</em>: We need to prove that A↔B implies B↔A. As A↔B there exists an invertible matrix P such that 
. In this equality we can perform a right multiplication by 
and obtain 
. Then, in the obtained equality we perform a left multiplication by P and get 
. If we write 
and 
we have 
. Thus, B↔A.
<em>Transitive</em>: We need to prove that A↔B and B↔C implies A↔C. From the fact A↔B we have and from B↔C we have 
. Now, if we substitute the last equality into the first one we get
.
Recall that if P and Q are invertible, then QP is invertible and 
. So, if we denote R=QP we obtained that
. Hence, A↔C.
Therefore, the relation is an <em>equivalence relation</em>.
Answer:
Step-by-step explanation:
ac = bc
ab = 4 sqr. 2 = 4² = 16
ab = 16
ab = ac = 16
the length of each legs is 16
So since there is a mixed number, 8 means there are 8 one-hundreds and 23 remaining ones. So, 800+23=823 ones. 823/100 as an improper fraction. since it is already out of 100, your job is easy. you now divide 823 by 100 (move the decimal over to the left 2 places) and you get 8.23 as a decimal. Hope i helped!!
