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Ostrovityanka [42]
3 years ago
11

If your desk is36 inches how many feet is it

Mathematics
2 answers:
yuradex [85]3 years ago
5 0
One foot is 12 inches, so 36 divided by 12 equals 3 feet.
snow_lady [41]3 years ago
4 0
THREE FEET. THE DESK IS THREE FEET TALL. I HEREBY ACKNOWLEDGE THAT THE NUMBER OF LEGS THE DESK HAS IS NOT RELEVANT. 
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When a cylindrical tank is filled with water at a rate of 22 cubic meters per hour, the level of water in the tank rises at a ra
Sergeu [11.5K]

Answer:

r=\sqrt{10}\text{ m}

Step-by-step explanation:

We have been given that when a cylindrical tank is filled with water at a rate of 22 cubic meters per hour, the level of water in the tank rises at a rate of 0.7 meters per hour. We are asked to find the approximate radius of tank in meters.

We will use volume of cylinder formula to solve our given problem as:

V=\pi r^2h, where,

r = Radius,

h = Height of cylinder.

Since the level of water in the tank rises at a rate of 0.7 meters per hour, so height of cylinder would be h = 0.7 meters at V=22\text{ m}^3.

Upon substituting these values in above formula, we will get:

22\text{ m}^3=\frac{22}{7}\cdot r^2(0.7\text{ m})

22\text{ m}^3=\frac{22}{10}\cdot r^2\text{ m}

\frac{10}{22}\cdot\frac{22\text{ m}^3}{\text{m}}=r^2

r^2=\frac{10}{22}\cdot\frac{22\text{ m}^3}{\text{m}}

r^2=10\text{ m}^2

Now, we will take positive square root of both sides as radius cannot be negative.

\sqrt{r^2}=\sqrt{10\text{ m}^2}

r=\sqrt{10}\text{ m}

Therefore, radius of tank would be approximately square root of 10 m.

5 0
2 years ago
6375/10000 in simplest form
Leto [7]
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3 0
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I need help please will mark brainliest
Simora [160]

Answer:

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Step-by-step explanation:

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4 0
3 years ago
Read 2 more answers
< ADF measures 2x degrees and < FDC measures x + 12 degrees. What is the measure
gtnhenbr [62]

Answer:

<h2>Angle ADF is equal to 52° and angle FDC is equal to 38°.</h2>

Step-by-step explanation:

In the image attaches, you can observe that angles ADF and FDC are complementary angles, because they sum 90°.

\angle ADF + \angle FDC = 90\°

And we know that

\angle ADF=2x\\\angle FDC = x+12

Replacing these expressions, we have

2x+x+12=90\°\\3x=90\° - 12\°\\x=\frac{78}{3}\\ x=26

Then, we replace this value in each expression to find both angles measures.

\angle ADF= 2(26)=52\°\\\angle FDC = 26+12=38\°

Therefore, angle ADF is equal to 52° and angle FDC is equal to 38°.

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