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motikmotik
3 years ago
7

Solve for x: 0.03x - 1.2 = 0.24

Mathematics
1 answer:
Gala2k [10]3 years ago
6 0

Answer:

920

Step-by-step explanation:

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Solve the equation<br> 15x+2=45x+4
BaLLatris [955]
15x + 2 = 45x + 4

Subtract 2 from both sides, as well as subtracting 45x from both sides.

15x - 45x = 4 - 2

-30x = 2

Divide both sides by -30.

x = 2/-30

x = - 1/15

~Hope I helped!~
5 0
2 years ago
What is the measure of XZW?
USPshnik [31]

Answer:

85 degrees

Step-by-step explanation:

3 0
2 years ago
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PC=PD then (PA)PC)=(PB)(___)
yKpoI14uk [10]

Answer:

PD is the answer

Step-by-step explanation:

(PA) (PC) = (PB) (PD)

6 0
3 years ago
Graph y &gt; x^2 - 5. Click on the graph until the correct one appears.
kenny6666 [7]

y=x^2\\\\for\ x=\pm2\to y=(\pm2)^2=4\to(-2;\ 4);\ (2;\ 4)\\\\for\ x=\pm1\to y=(\pm1)^2=1\to (-1;\ 1);\ (1;\ 1)\\\\for\ x=0\to y=0^2=0\to (0;\ 0)

Shift the graph of the function y = x², 5 units down /look at the picture #1/.

y > x^2-5 /look at the picture #2/ - your answer

7 0
3 years ago
Read 2 more answers
CALCULUS EXPERT WANTED
Vlad [161]

a. Use the mean value theorem. 16 falls between 12 and 20, so

v'(16)\approx\dfrac{v(20)-v(12)}{20-12}=\dfrac{240-200}8=5

(Don't forget your units - 5 m/min^2)

b. v(t) gives the Johanna's velocity at time t. The magnitude of her velocity, or speed, is |v(t)|. Integrating this would tell us the total distance she has traveled whilst jogging.

The Riemann sum approximates the integral as

\displaystyle\int_0^{40}|v(t)|\,\mathrm dt=12\cdot200+8\cdot240+4\cdot220+16\cdot150=7600

If you're not sure how this is derived: we're given 5 sample points, so we can cut the interval [0, 40] into 4 subintervals. The lengths of each subinterval are 12, 8, 4, and 16 (the distances between each sample point), and the height of the rectangle approximating the area under the plot of |v(t)| is determined by the value of v(t) at each sample point, 200, 240, |-220| = 220, and 150.

c. Bob's velocity is given by B(t), so his acceleration is given by B'(t). We have

B'(t)=3t^2-12t

and at t=5 his acceleration is B'(5)=15 m/min^2.

d. Bob's average velocity over [0, 10] is given by the difference quotient,

\dfrac{B(10)-B(0)}{10-0}=\dfrac{700-300}{10}=40 m/min

6 0
3 years ago
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