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Degger [83]
3 years ago
10

Simplify the expression. 9(-10-4v)+9v

Mathematics
2 answers:
I am Lyosha [343]3 years ago
6 0

Answer: -90-27v

Step-by-step explanation:

N A

padilas [110]3 years ago
5 0

Answer:

-90-27v

Step-by-step explanation:

9(-10-4v)+9v

-90 - 36v + 9v

-90 - 27v

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3(x+6)2=75 show steps
nexus9112 [7]

Answer:

6.5

Step-by-step explanation:

3(x+6)2=75 | Given

6x + 36 = 75 | Distribute

6x = 39 | Subtract 36 from both sides

x = 6.5

7 0
3 years ago
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Step-by-step explanation:

4 0
3 years ago
What's the next letter? Y b w d u f
Vera_Pavlovna [14]
 z y x w v u t s r
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S is the answer
8 0
2 years ago
Martina is currently 16 years older than her cousin Joey. In 5 years she will be 3 times as old as Joey. Use this information to
marishachu [46]
<span>m = j + 16
m + 5 = 3j
---
put the system of linear equations into standard form
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m - j = 16
m - 3j = -5
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x - y = 16
x - 3y = -5

so now that you have your equations formed, just solve. 

x - y = 16 , which means that x = y + 16 
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8 0
3 years ago
Read 2 more answers
A chord consists of notes that sound good together. The C major chord starting at middle C has the following frequencies: C - 26
Bingel [31]

Answer:

The frequency of note E is:

f(E) = 330 Hz

The frequency of note C is:

f(C) = 262 Hz

The ratio of the frequency of note E to the frequency of note C is just the quotient of these two frequencies:

r  = f(E)/f(C) = 330Hz/262Hz = 330/262 = 1.26

Now, we want to find how man E waves will fit in the length of four C waves.

Note that here the word "length" is used, so we need to work with the wavelengths, not with the frequencies.

For waves, we have the relationship:

v = f*λ

where:

v = velocity (in this case, velocity of the sound = 343 m/s)

f = frequency

λ = wavelength.

So, the length of a single E wave is:

λ(E) = (343 m/s)/(330 1/s) = 1.04 m

And the length of a single C note is:

λ(C) = (343 m/s)/(262 1/s) = 1.30 m

In four C waves, the length is:

4*λ(C) = 4*1.30m = 5.2m

The number of E waves that fit in the length of four C waves is equal to the quotient between the length of four C waves and one E wave:

N = (4*λ(C))/(λ(E) ) = (5.2 m)/(1.04m) = 5.14

So we can fit 5 E waves into four C waves.

6 0
3 years ago
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