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Soloha48 [4]
3 years ago
10

Solve the following question ​

Mathematics
1 answer:
nydimaria [60]3 years ago
5 0

9514 1404 393

Answer:

  π/3

Step-by-step explanation:

The given integral does not exist. We assume there is a typo in the upper limit, and that you want the integral whose upper limit is (√3)/2.

It is convenient to make the substitution ...

  x = sin(y) . . . . so, y = arcsin(x)

 dx = cos(y)·dy

Then the integral is ...

  \displaystyle\int_0^{\sqrt{3}/2}{\dfrac{\cos{y}}{\sqrt{1-\sin^2{y}}}}\,dy=\int_0^{\sqrt{3}/2}{dy}=\left.\arcsin{x}\right|\limits_0^{\sqrt{3}/2}\\\\=\arcsin{(\sqrt{3}/2)}=\boxed{\dfrac{\pi}{3}}

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Step-by-step explanation:

7 0
4 years ago
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Solve the equation<br> 2x-3=15<br> A)x=6<br> B)x=9<br> C)x=24<br> D)x=36
DaniilM [7]
To solve the equation, it is necessary to isolate the unknown variable "x" first. This is done as shown below:

2x - 3 = 15

Adding 3 to both sides of the equation:

2x - 3 + 3 = 15 + 3
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Dividing 2 from both sides:

2x/2 = 18/2
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Among the choices, the correct answer is B.
5 0
4 years ago
<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B2x%7D%7B5%7D%20%3D%209%20-%20%20%5Cfrac%7Bx%7D%7B2%7D%20" id="TexFormula1" title=
Ray Of Light [21]

Add \frac{x}{2} to both sides:

\dfrac{2x}{5}+\frac{x}{2} = 9

Add the fractions in the left hand side:

\dfrac{2x}{5}+\frac{x}{2} = \dfrac{4x}{10}+\frac{5x}{10}=\dfrac{9x}{10}

So, the equation becomes

\dfrac{9x}{10}= 9

Multiply both sides by 10:

9x = 90

Divide both sides by 9:

x = 10

5 0
4 years ago
Please someone help with this question
ella [17]

Answer:

4th option: a= 12ft, b= 12ft

Step-by-step explanation:

Please see attached picture for full solution.

6 0
3 years ago
Hiii please help i’ll give brainliest if you give a correct answer ty!!
Marat540 [252]

Answer:C, E is my answer i believe

4 0
3 years ago
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