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Soloha48 [4]
3 years ago
10

Solve the following question ​

Mathematics
1 answer:
nydimaria [60]3 years ago
5 0

9514 1404 393

Answer:

  π/3

Step-by-step explanation:

The given integral does not exist. We assume there is a typo in the upper limit, and that you want the integral whose upper limit is (√3)/2.

It is convenient to make the substitution ...

  x = sin(y) . . . . so, y = arcsin(x)

 dx = cos(y)·dy

Then the integral is ...

  \displaystyle\int_0^{\sqrt{3}/2}{\dfrac{\cos{y}}{\sqrt{1-\sin^2{y}}}}\,dy=\int_0^{\sqrt{3}/2}{dy}=\left.\arcsin{x}\right|\limits_0^{\sqrt{3}/2}\\\\=\arcsin{(\sqrt{3}/2)}=\boxed{\dfrac{\pi}{3}}

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Write the coordinates of the vertices after a reflection across the line y = 2.
rewona [7]

P' =  (-1, 8)  (the x coordinate stays the same and the y coordinate =  (distance between -4 and 2)  + 2 =  6+2 = 8).

using the same  process:-

Q' = (4, 8)

R' =  (8, 5)

S' = (3, 5)


4 0
4 years ago
If U = {x: X € N, 1 < × < 15)
Inessa05 [86]

Answer:

Step-by-step explanation:

Given:

U = {x: X € N, 1 < × < 15) = {1,2,3,4,5,6,7,8,9,10,11,12,13,14,15}

A = {2,4,6,8,10,12,14}

B = {3,6,9,12,15}

C = {5,10,15}

(a) Verify A(BnB)=(AUB)(AUB)

A U (B n B)

=  {2,4,6,8,10,12,14} U (  {3,6,9,12,15} n  {3,6,9,12,15} )

=  {2,4,6,8,10,12,14} U {3,6,9,12,15}

=  {2,3,4,6,8,9,10,12,14,15}

( A U B) n (A U B)

= {2,3,4,6,8,9,10,12,14,15} n {2,3,4,6,8,9,10,12,14,15}

= {2,3,4,6,8,9,10,12,14,15}

Therefore

A U (B n B)  =  ( A U B) n (A U B)

verifies

(b) Verify An(BUC)=(AnB)u(AnC)

A n ( B U C)

=  {2,4,6,8,10,12,14} n ( {3,6,9,12,15} U {5,10,15} )

=  {2,4,6,8,10,12,14} n {3,5,6,9,10,12,15}

= {6,10,12}

( A n B ) U ( A n C )

= ( {2,4,6,8,10,12,14} n {3,6,9,12,15} ) U ( {2,4,6,8,10,12,14} n {5,10,15} )

= {6,12} U {10}

= {6,10,12}

Therefore

A n ( B U C) = ( A n B ) U ( A n C )

verifies

(c) Verify AU(BUC)=(AUB)U(AUC)​

AU(BUC)

=  {2,4,6,8,10,12,14}U{3,6,9,12,15}U{5,10,15}

= {2,3,4,5,6,8,9,10,12,14,15}

(AUB)U(AUC)​

=  ({2,4,6,8,10,12,14}{3,6,9,12,15})U({2,4,6,8,10,12,14}U{5,10,15})

= {2,3,4,6,8,9,10,12,14,15}U{2,4,5,6,8,10,12,14,15}

= {2,3,4,5,6,8,9,10,12,14,15}

Therefore

AU(BUC)=(AUB)U(AUC)​

verifies

5 0
3 years ago
Larissa plans to bake at most 10 loaves of bread. She makes x loaves of banana bread that sell for $1.25 each and y loaves of nu
Veseljchak [2.6K]

Answer:

1) The system of inequalities are;

x × 1.25 + y × 1.5 ≥ 24

x + y ≤ 10

Please find attached the required graph of the two inequalities ,created with Microsoft Excel

2) The graph of inequality shows that Larissa cannot to make less than 10 loafs of bread and sell them for over $24 at the given prices of each loaf of bread

Step-by-step explanation:

1) The maximum number of loaves Larissa plans to make = 10

The price at which she sells each of x loaves of banana bread = $1.25

The price at which she sells each of y loaves of nut bread = $1.50

The total amount she hopes to make = $24

The system of inequalities are;

x × 1.25 + y × 1.5 ≥ 24

x + y ≤ 10

Making y the subject of both inequalities gives;

For the first inequality, we have,

y ≥ 24/1.5 - 1.25/1.5·x which gives;

y ≥ 16 - 5/6·x

For the second inequality, we have,

y ≤ 10 - x

Please find attached the required graph of the two inequalities

2) From the attached graph of inequality, created with Microsoft Excel, it shows that it is not possible for Larissa to make less than 10 loafs of bread and at the same time sell them for over $24 if the price of each banana bread is $1.25 and the price of each nut bread is $1.50.

3 0
3 years ago
Irrational numbers cannot be written as a ratio…irrational means not rational. All fractions of integers are Rational.
TiliK225 [7]

with the exception of perfect squares, all square root of whole numbers are irrational, e.g. √5

how about this one:

2.34334333433334.... I am increasing the number of 3s each time, thus

creating a decimal which never ends and never repeats.

or

12.3456789101112131415.... can you see what I am doing?

will it ever end? will it ever repeat?

3 0
3 years ago
In the figure below, Angle ADC measures 50 degrees, and Angle BAC measures 90 degrees. What is the measure of Angle BAD?
juin [17]
Well I do not see the figure but I will assume it is a triangle. there are 3 angles in a triangle. Those 3 angles add up to 180. Since we know this, you can use the equation
angle1 + angle2 + angle3 = 180

we have 2 of the angles so with a little algebra we can solve for the last angle like this
180 - angle1 - angle2 = angle3

plug in 2 angles
180 - 50 - 90 = angle3

So answer is
angle3 = 40 degrees
6 0
4 years ago
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