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prohojiy [21]
3 years ago
11

Help please! my teacher wants us to show how we got our answer

Mathematics
1 answer:
Mila [183]3 years ago
3 0

Direct variation is when \dfrac{y}{x} is the same for each coordinate.

Indirect variation is when x · y is the same for each coordinate.

11. Answer:  Direct Variation

<u>Step-by-step explanation:</u>

\begin {array}{c||c|c|c|c|c}x&12&18&23&29&34\\y&132&198&253&319&374\\\\\dfrac{y}{x}&\dfrac{132}{12}=11&\dfrac{198}{18}=11&\dfrac{253}{23}=11&\dfrac{319}{29}=11&\dfrac{374}{34}=11\\\end{array} \\\\\\\text{The coordinates x and y show a direct variation.}

12. Answer: Indirect Variation

<u>Step-by-step explanation:</u>

\begin {array}{c||c|c|c|c|c}x&4&6&8&8.4&12\\y&21&14&10.5&10&7\\x\cdot y&4\cdot 21=84&6\cdot 14=84&8\cdot 10.5=84&8.4\cdot 10=84&12\cdot 7=84\\\end{array} \\\\\\\text{The coordinates x and y show an indirect variation.}

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Information given

314 305 344 283 285 310​ 383​ 285​ 300​ 300

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\bar X =\frac{\sum_{i=1}^n X_i}{n}

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s=31.09 represent the standard deviation for the sample      

n=10 sample size      

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\alpha=0.05 represent the significance level

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p_v represent the p value

Hypothesis to test

We want to verify if the true mean is greater than 300, the system of hypothesis would be:      

Null hypothesis:\mu \leq 300      

Alternative hypothesis:\mu > 300      

The statistic is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)      

Replacing the info given we got:

t=\frac{310.9-300}{\frac{31.09}{\sqrt{10}}}=1.109      

The degrees of freedom are given by:

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And the p value would be given by:

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Since the p value is higher than the significance level of 0.05 we don't have enough evidence to conclude that the true mean is significantly higher than $300 because we FAIL to reject the null hypothesis.

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