grades are due tomorrow morning and ive been struggling really bad. this is the app that has been helping me pass. i’ll give bra
inlisest. just please help !!
1 answer:
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Answer:
The height of the cliff CD is approximately 539.76 m
Step-by-step explanation:
The given parameters are;
The first angle of elevation with which the captain sees the person on the cliff = 61°
The second angle of elevation with which the captain sees the person on the cliff after moving 92 m closer to the cliff = 69°
The angle made by the adjacent supplementary angle to the second angle of elevation = 180° - 69° = 111°
∴ Whereby, the rays from the first and second angle of elevation and the distance the ship moves closer to the cliff forms an imaginary triangle, we have;
The angle in the imaginary triangle subtended by the distance the ship moves closer to the cliff = 180° - 111° - 61° = 8°
By sine rule, we have;
AB/(sin(a)) = BC/(sin(c))
Which gives;
92/(sin(8°)) = BC/(sin(61°))
BC = (sin(61°)) × 92/(sin(8°)) ≈ 578.165 m
BC ≈ 578.165 m
The height CD = BC × sin(69°)
∴ The height of the cliff CD = 578.165 m × sin(69°) ≈ 539.76 m.
The height of the cliff CD ≈ 539.76 m.
Answer:
352 ft²
Step-by-step explanation:
The formula for the area of a trapezoid is where
and
are the bases of the trapezoid and
is the height, thus:
This means that the area of the trapezoid is 352 ft².