All categories

3 years ago

Please help me solve

Mathematics

1 answer:

vlabodo [156]3 years ago

4 0

(2x+5)=Inscribed Angle
50 = Arc Length
Inscribed Angle=1/2Arc Length
2x+5=1/2(50)
2x+5=25
2x=20
X=10

You might be interested in

X+y= 275<br> 75 + 50 = 200<br><br><br> it’s system of equations

Wewaii [24]

Answer:

Its either x=273 or the given system has no solution.

Step-by-step explanation:

Solution by substitution method

x+y=275

and 75+50=200

∴0=75

a1/a2=10=Undefined

b1/b2=10=Undefined

c1/c2=-275/-75=3.6667

∴a1/a2 =b1/b2≠c1/c2

the given system has no solution.

5 0

3 years ago

A playground is rectangular with a length of 78 miles. If the area of the playground is 820 square miles, what is its width? Inp

Rudiy27

Answer:

10.5, $10\frac{1}{2}$ , or $\frac{21}{2}$

Step-by-step explanation:

To solve, you can use a variable (x) to represent the width.

The equation for area is A=L×W

So the Area is 820 and the length is 78.

820= 78w

Isolate the variable to solve.

w=10.5128....

If you round, it will be 10.5

10.5 as a fraction is $10\frac{1}{2}$ or $\frac{21}{2}$

8 0

2 years ago

Question

Kisachek [45]

450-120=330
55*6=330
6 weeks

6 0

3 years ago

A right triangle abc is similar to triangle pqr such that the hypotenuse bc=10 and the hypotenuse qr=4. if ac=8, what is the len

adoni [48]

Because the triangles are similar

ac/pr=bc/qr
8/pr=10/4

10*pr=8*4
10pr=32
pr=32/10
pr=3,2

7 0

3 years ago

1. Remember what we know about vertical angles and solve for x. (SHOW WORK)

EastWind [94]

Answer:

Ans.1.) X = 7.

Ans.2.a.) AC =JL.

Ans.2.b.) BC = KL.

Step-by-step explanation:

For Question 1.

As we know vertically opposite angles are equal.

$\therefore (x+16)\° = (4x-5)\°\\\therefore (5+16)\° = (4x-x)\°\\ \therefore (3x) = (21)\\\therefore x = 7\\$

For Question 2.a)

$In\ \triangle ABC and \triangle JKL \\AB \cong JK\ \textrm{Given}\\\angle CAB \cong \angle LJK\ \textrm{each measure angle of 90\°}\\AC \cong JL\ \textrm{this is the required information to prove the triangles are congruent by SAS postulate}\\\therefore \triangle ABC \cong \triangle JKL\ \textrm{ By SAS postulate}$

For Question 2.b)

$In\ \triangle ABC and \triangle JKL \\AB \cong JK\ \textrm{Given}\\\angle CAB \cong \angle LJK\ \textrm{each measure angle of 90\°}\\BC \cong KL\ \textrm{this is the required information to prove the triangles are congruent by HL Theorem}\\\therefore \triangle ABC \cong \triangle JKL\ \textrm{ By Hypotenuse length Theorem}$

3 0

3 years ago