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3 years ago

Which is an example of quantitative data?

Mathematics

2 answers:

mixer [17]3 years ago

8 0

Answer:

A. the number of textbooks in a classroom

Step-by-step explanation:

quantitative data is information about quantities; that is, information that can be measured and written down with numbers.

nlexa [21]3 years ago

7 0

Answer A
Hope this helps :)

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Tables do not include numerical data. True or false?

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True all table does not need to include numerical data

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At a local store, Kelly and Martin bought some notebooks and pencils. Kelly bought 4 notebooks and 25 pencils for 16.71. Martin

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9.17

Step-by-step explanation:

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3 years ago

A large high school offers AP Statistics and AP Calculus Among the seniors in this school 65% take AP Statistics, 45% take AP Ca

Igoryamba

Answer:

0.8

Step-by-step explanation:

P(AP statistics) = 65%

P(AP Calculus) = 45%

P(AP statistics n AP Calculus) = 30%

Probability of AP statistics or AP Calculus but not both :

Probability of event A or B :

P(AUB) = p(A) + p(B) - p(AnB)

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= 0.65 + 0.45 - 0.30

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2 years ago

in order to encourage students to show up early to a school dance , the dance comittee decides to charge less for those who come

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3 years ago

<img src="https://tex.z-dn.net/?f=9%5C%3A%20%20%5C%3A%20%20%5Cfrac%7B%20%5Csin%28%20%5Ctheta%29%20%7D%7B1%20%2B%20%20%5Ccos%28%2

PIT_PIT [208]

Option (b) is your correct answer.

Step-by-step explanation:

$\large\underline{\sf{Solution-}}$

Given Trigonometric expression is

$\rm :\longmapsto\:\dfrac{sin\theta }{1 + cos\theta }$

So, on rationalizing the denominator, we get

$\rm \: = \: \dfrac{sin\theta }{1 + cos\theta } \times \dfrac{1 - cos\theta }{1 - cos\theta }$

We know,

$\purple{\rm :\longmapsto\:\boxed{\tt{ (x + y)(x - y) = {x}^{2} - {y}^{2} \: }}}$

So, using this, we get

$\rm \: = \: \dfrac{sin\theta (1 - cos\theta )}{1 - {cos}^{2}\theta }$

We know,

$\purple{\rm :\longmapsto\:\boxed{\tt{ {sin}^{2}x + {cos}^{2}x = 1}}}$

So, using this identity, we get

$\rm \: = \: \dfrac{sin\theta (1 - cos\theta )}{{sin}^{2}\theta }$

$\rm \: = \: \dfrac{1 - cos\theta }{sin\theta }$

<u>Hence, </u>

$\\ \red{\rm\implies \:\boxed{\tt{ \rm \:\dfrac{sin\theta }{1 + cos\theta } = \: \dfrac{1 - cos\theta }{sin\theta } }}} \\$

3 0

2 years ago

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