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goblinko [34]
3 years ago
11

Giving out extra points and marking brainliest, need help fast

Mathematics
1 answer:
maks197457 [2]3 years ago
4 0

Answer:

x=43.3

Step-by-step explanation:

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Which of the following shows the division problem below in synthetic division form?
MissTica

Answer:

Choice D

Step-by-step explanation:

Given division problem is \frac{5x^2+9x-6}{x+2}

Now we need to find about which of the given choices shows the division problem below in synthetic division form.

To convert into synthetic division form, we set denominator =0 so we get

x+2=0 or x=-2

Hence we divide by -2

Now collect coefficients of numerator for the dividend part

Coefficients of  5x^2+9x-6 are 5 9 -6

Hence correct choice is D

8 0
4 years ago
Read 2 more answers
NEED HELP ASAP! <br> Slove for x.<br><br> A.4<br> B.10 <br> C.8<br> D.7
evablogger [386]

i think it 10 because the angle your looking at is x is 7

3 0
3 years ago
PLEASE HELP!!
likoan [24]

Answer:

are you using math solver app

6 0
3 years ago
Read 2 more answers
Identify the solution set for: −2|−2x−4|=−12
myrzilka [38]

Answer:

C: {−5, 1)

Step-by-step explanation:

Starting with −2|−2x−4|=−12, divide both sides by -2:

|−2x−4| =  6

Reduce this by dividing all terms by 2:

|-x - 2| = 3

This is equivalent to   x + 2 = 3  and  x + 2 = - 3

Solving thse two equations, we get x = 1 and x = -5

And so the solution set is  C: {−5, 1)

4 0
3 years ago
Read 2 more answers
Mr. Steiner purchased a car for about $14,000. Assuming his loan was
djverab [1.8K]

Answer:

$415.18

Explanation:

The calculation of the present value of a cash flow or other income stream that produces $1 in income over so many periods of time.

DATA

Amount borrowed = $12,500

Annual interest rate = 12.00%

Monthly interest rate = 1.00%

Period = 36 months

Let monthly payment be x

12,500 = x/1.01 + x/1.01^2 + x/1.01^3  … + x/1.01^35 + x/1.01^36

12,500 = x * (1 - (1/1.01)^36) / 0.01

12,500 = x * 30.107505

x = 12,500/30.107505  

x = 415.18

The monthly payment is $415.18

5 0
3 years ago
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