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2 years ago

Mr. Steiner purchased a car for about $14,000. Assuming his loan was

Mathematics

1 answer:

djverab [1.8K]2 years ago

5 0

Answer:

$415.18

Explanation:

The calculation of the present value of a cash flow or other income stream that produces $1 in income over so many periods of time.

DATA

Amount borrowed = $12,500

Annual interest rate = 12.00%

Monthly interest rate = 1.00%

Period = 36 months

Let monthly payment be x

12,500 = x/1.01 + x/1.01^2 + x/1.01^3 … + x/1.01^35 + x/1.01^36

12,500 = x * (1 - (1/1.01)^36) / 0.01

12,500 = x * 30.107505

x = 12,500/30.107505

x = 415.18

The monthly payment is $415.18

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Evaluate 17 + 70/x when x = 14.

kipiarov [429]

Answer:

34.5

Step-by-step explanation:

17 + 70/x when x = 14.

substitute x for 14

17 + 70/4

17 + 17.5

34.5

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2 years ago

7 × (–3) × (–2)^2 =

skad [1K]

<span>7 × (–3) × (–2)^2
= </span>-21 × 4
= - 84

Hope it helps

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2 years ago

Read 2 more answers

Suppose an investment account is opened with an initial deposit of $11,000 earning 7.2% interest. Round all answers to the neare

Bingel [31]

Answer:$800 to the nearest dollar

Step-by-step explanation:

To find this

7.2/100×$11000

=$792

To the nearest dollar

$800

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2 years ago

the number of points in the first five games of the football season are listed below. what is the mean number of points scored?

yarga [219]

^ You again? Quit being sus and answer the question here instead of elsewhere.

To find the mean, all you have to do is add each number and then divide by how many numbers you added.

So, 38 + 29 + 16 + 42 + 33 = 158. There were five numbers added, so the next step is to divide 158 by 5. That equals 31.6 as your answer.

3 0

2 years ago

The average score of all pro golfers for a particular course has a mean of 70 and a standard deviation of 3.0 (Think of these as

bija089 [108]

Answer:

0.477 is the probability that the average score of the 36 golfers was between 70 and 71.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 70

Standard Deviation, σ = 3

Sample size, n = 36

Let the average score of all pro golfers follow a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

P(score of the 36 golfers was between 70 and 71)

$\text{Standard error of sampling} = \displaystyle\frac{\sigma}{\sqrt{n}} = \frac{3}{\sqrt{36}} = \frac{1}{2}$

$P(70 \leq x \leq 71) = P(\displaystyle\frac{70 - 70}{\frac{3}{\sqrt{36}}} \leq z \leq \displaystyle\frac{71-70}{\frac{3}{\sqrt{36}}}) = P(0 \leq z \leq 2)\\\\= P(z \leq 2) - P(z \leq 0)\\= 0.977 - 0.500 = 0.477= 47.7\%$

$P(70 \leq x \leq 71) = 47.7\%$

0.477 is the probability that the average score of the 36 golfers was between 70 and 71.

8 0

2 years ago