Arrange an 8-, 12-, and 16-Ω resistor in a combination that has a total resistance of 8.89 Ω pls with de work
1 answer:
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<h2>Hey There!</h2><h2>_____________________________________</h2><h2>Answer:</h2>
mass = 4 kg
velocity = 5 m/s^2
<h3 /><h3>Orange truck:</h3>Mass= 2kg
Velocity = 7m/s^2
<h3 /><h3>Grey Car:</h3>mass = 6 kg
velocity = 4m/s^2
<h3 /><h3>Green Car:</h3>Mass = 8 kg
Velocity = 3 m/s^2
<h2>_____________________________________</h2><h2>SOLUTION:</h2>By the equation of kinetic energy,
K.E =
Where,
K.E is kinetic energy
m is mass
v is velocity
<h2>_____________________________________</h2><h3>Kinetic energy of Blue car:</h3>
Directly substitute the variables in the equation,
K.E =
Simplify the equation,
K.E = 50 J
<h2>_____________________________________</h2><h3>Kinetic Energy of Silver Car:</h3>
Directly substitude the variable in the equation,
K.E =
Simplify the equation,
K.E = 48J
<h2>_____________________________________</h2><h3>Kinetic Energy of Green Car:</h3><h3 />Substitute the variables in the equation,
K.E =
Simplify the Equation,
K.E = 36J
<h2>_____________________________________</h2><h3>Kinetic Energy of Orange Truck:</h3><h3 />Substitute the variable,
K.E =
Simplify the equation,
K.E = 49J
<h2>_____________________________________</h2>As you can see that the highest value of kinetic energy is of Blue SUV thus it will be out answer.
<h2>_____________________________________</h2><h2>Best Regards,</h2><h2>'Borz'</h2><h3 /><h3 /><h3 /><h3 /><h2 /><h2 />
Answer:
(a) Magnitude of static friction force is 109 N
(b) Minimum possible value of static friction is 0.356
Solution:
As per the question;
Horizontal force exerted by the girl, F = 109 N
Mass of the crate, m = 31.2 kg
Now,
(a) To calculate the magnitude of static friction force:
Since, the crate is at rest, the forces on the crate are balanced and thus the horizontal force is equal to the frictional force, f:
F = f = 109 N
(b) The maximum possible force of friction between the floor and the crate is given by:
where
N = Normal reaction = mg
Thus
For the crate to remain at rest, The force exerted on the crate must be less than or equal to the maximum force of friction.
Answer:
q = 4.5 nC
Explanation:
given,
electric field of small charged object, E = 180000 N/C
distance between them, r = 1.5 cm = 0.015 m
using equation of electric field
k = 9 x 10⁹ N.m²/C²
q is the charge of the object
now,
q = 4.5 x 10⁻⁹ C
q = 4.5 nC
the charge on the object is equal to 4.5 nC