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3 years ago

Arrange an 8-, 12-, and 16-Ω resistor in a combination that has a total resistance of 8.89 Ω pls with de work

Physics

1 answer:

kolezko [41]3 years ago

8 0

20 ohms in parallel with 16 ohm= 8.89

20x16/20+16. Product over sum

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Ik you didnt do the lab but like idek...

serious [3.7K]

Answer:

Speed and direction affect pitch.

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3 years ago

A particle is moving along a circular path of 2-m radius such that its position as a function of time is given by u = (5t 2) rad

OverLord2011 [107]

Answer:

Explanation:

Given

radius of path $r=2\ m$

Velocity of Particle $\theta =5t^2 rad$

where t=time in seconds

angular velocity of particle is given by

$\omega =\frac{\mathrm{d} \theta }{\mathrm{d} t}$

$\omega =2\times 5t=10\cdot t$

And angular acceleration is given by

$\alpha =\frac{\mathrm{d} \omega }{\mathrm{d} t}$

$\alpha =10 rad/s^2$

tangential acceleration is $a_t=\alpha \times r$

$a_t=10\times 2=20\ m/s^2$

Centripetal acceleration $a_c=\omega ^2\times r$

$a_c=(10t)^2\times 2=200t^2$

net acceleration is sum of tangential and centripetal force at any time t is given by

$a_{net}=\sqrt{(a_c)^2+(a_t)^2}$

$a_{net}=\sqrt{(200t)^2+(20)^2}$

$a_{net}=20\sqrt{(10t)^2+1}\ m/s$

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3 years ago

Which of the following would most likely happen if water did not form hydrogen bonds?

Trava [24]

Option C is the correct answer

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4 years ago

If a yo-yo is spinning so that it makes 240 revolutions every minute, what is its period?

Aleksandr-060686 [28]

Answer: 0.25 seconds.

Explanation:

The yo-yo does 240 revolutions in one minute, and we know that one minute has 60 seconds, then the revolutions per second can be calculated as:

240 rev/60s = 4 rev/s, this will be the frequency of the yo-yo

The frequency is actually written as: f = 4 Hz = 4 s^-1

We want to find the period of this yo-yo.

The period is the duration of one cycle, and we have the relation:

f = 1/T

Where f is the frequency and T is the period, then:

T = 1/f

And we know the value of f, it is f = 4 s^-1

Then the period will be:

T = 1/(4 s^-1) = (1/4) s

Then the period of the yo-yo is 1/4 seconds = 0.25 seconds.

4 0

3 years ago

A tourist being chased by an angry bear is running in a straight line toward his car at a speed of 4.2 m/s. The car is a distanc

dem82 [27]

Explanation:

It is known that the relation between speed and distance is as follows.

velocity = $\frac{distance}{time}$

As it is given that velocity is 6 m/s and distance traveled by the bear is (d + 29). Therefore, time taken by the bear is calculated as follows.

$t_{bear} = \frac{(d + 29)}{6 m/s}$ ............. (1)

As the tourist is running in a car at a velocity of 4.2 m/s. Hence, time taken by the tourist is as follows.

$t_{tourist} = \frac{d}{4.2}$ ............. (2)

Now, equation both equations (1) and (2) equal to each other we will calculate the value of d as follows.

$t_{bear} = t_{tourist}$

$\frac{(d + 29)}{6 m/s}$ = $\frac{d}{4.2}$

4.2d + 121.8 = 6d

d = $\frac{121.8}{1.8}$

= 67.66

Thus, we can conclude that the maximum possible value for d is 67.66.

5 0

3 years ago