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Eduardwww [97]
3 years ago
8

Arrange an 8-, 12-, and 16-Ω resistor in a combination that has a total resistance of 8.89 Ω pls with de work

Physics
1 answer:
kolezko [41]3 years ago
8 0


20 ohms in parallel with 16 ohm= 8.89

20x16/20+16. Product over sum


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The sun rotates once in 25.05 days. That is 601.2 hours. so the sun's rotational speed is 0.0017 rotations per hour. what is the
Margaret [11]

Answer:

v=2019.09\ m.s^{-1}

Explanation:

Given:

  • time taken by the sun to complete one revolution, t=601.2\ hr
  • radial distance of the sunspot, r=6.955\times 10^8\ m.s^{-1}

<u>Therefore, angular speed of rotation of sun:</u>

\omega=\frac{2\pi}{601.2\times 3600} \ rad.s^{-1}

<u>Now the tangential velocity of the sunspot can be given by:</u>

v=r.\omega

v=6.955\times 10^8\times \frac{2\pi}{601.2\times 3600}

v=2019.09\ m.s^{-1}

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3 years ago
The geocentric theory states that the center of the universe is
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4 years ago
Open Meet and enter this code: jnw-xodp-yij​
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Answer:

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Explanation:

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5 0
3 years ago
Read 2 more answers
Electromagnetic radiation of 8.12×10¹⁸ Hz frequency is applied on a metal surface and caused electron emission. Determine the wo
klemol [59]

Answer:

The work function ϕ of the metal = 53.4196 x 10⁻¹⁶ J      

Explanation:

When light is incident on a photoelectric material like metal, photoelectrons are emitted from the surface of the metal. This process is called photoelectric effect.

The relationship between the maximum kinetic energy (E_{k}) of the photoelectrons to the frequency of the absorbed photons (f) and the threshold frequency (f₀) of the photoemissive metal surface is:

                                        E_{k} = h(f − f₀)

                                        E_{k} = hf - hf₀

E is the energy of the absorbed photons:  E = hf

ϕ is the work function of the surface:  ϕ = hf₀

                                        E_{k} = E - ϕ

Frequency f = 8.12×10¹⁸ Hz

Maximum kinetic energy E_{k} = 4.16×10⁻¹⁷ J  

Speed of light  c = 3 x 10⁸ m/s

Planck's constant h = 6.63 × 10⁻³⁴ Js                                

                                        E = hf = 6.63 × 10⁻³⁴ x 8.12×10¹⁸

                                        E = 53.8356 x 10⁻¹⁶ J

from E_{k} = E - ϕ ;

                                        ϕ = E - E_{k}

                                        ϕ = 53.8356 x 10⁻¹⁶ - 4.16×10⁻¹⁷

                                        ϕ = 53.4196 x 10⁻¹⁶ J

The work function of the metal ϕ = 53.4196 x 10⁻¹⁶ J      

4 0
3 years ago
4. Think back to Coulomb's Law. Two coins with identical charges are placed on a lab table 1.35 m apart.
FinnZ [79.3K]
A) To calculate the charge of each coin, we must apply the expression of the Coulomb's Law:
 
 F=K(q1xq2)/r²
 
 F: The magnitud of the force between the charges. (F=2.0 N).
 K: Constant of proporcionality of the Coulomb's Law (K=9x10^9 Nxm²/C²).
 q1 and q2: Electrical charges.
 r: The distance between the charges (r=1.35 m).
 
 We have the values of F, K and r, so we can calculate q1xq2, because both<span> coins have  identical charges:
</span> 
 q1xq2=(r²xF)/K
 q1xq2=(1.35 m)²(2.0 N)/9x10^9 Nxm²/C²
 q1xq2=3x10^-10 C
 q1=q2=(<span>3x10^-10 C)/2
 
 </span>Then, the charge of each coin, is:
<span> 
 q1=1.5x</span><span>10^-10 C 
 
 </span>q2=1.5x10^-10 C

B) <span>Would the force be classified as a force of attraction or repulsion?
</span> 
 It is a force of repulsion, because both coins have identical charges and both are postive. In others words, when two bodies have identical charges (positive charges or negative charges), the force is of repulsion.
5 0
3 years ago
Read 2 more answers
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